Answer:
D. is always perpendicular to the surface of the conductor
Explanation:
1) Answer is (D) option. Electric field just outside surface of charged conductor is normal to conductor at that point.
It can be explained on the basis of the fact that, Electric field inside conductor under static condition is zero. As a result potential difference between any two points with in conductor is zero. So whole of conductor is equipotential body.
Equipotential surface and Electric field lines always cut at 90 degrees to each other. Conductor being equipotential body, Electric field lines starting or terminating at conductor must be normal to surface. Hence electric field just outside conductor is perpendicular or normal to surface.
Crushing pressure. Human bodies are used to air pressure. The air pressure in our lungs, ears and stomachs is the same as the air pressure outside of our bodies, which ensures that we don't get crushed. Our bodies are also flexible enough to cope when the internal and external pressures aren't exactly the same.
Answer:
The work done is -209.42 J.
Explanation:
F(x) = (- 20 - 3 x ) N
x = 0 to x = 6.9 m
Here, the force is variable in nature, so the work done by the variable force is given by
![W =\int F dx\\\\W =\int_{0}^{6.9}(-20- 3x dx )\\\\W= \left [ - 20 x - 1.5 x^2 \right ]_{0}^{6.9}\\\\W = - 20 (6.9 - 0) - 1.5(6.9\times 6.9 - 0)\\\\W =- 138 - 71.42\\\\W = - 209.42 J](https://tex.z-dn.net/?f=W%20%3D%5Cint%20F%20dx%5C%5C%5C%5CW%20%3D%5Cint_%7B0%7D%5E%7B6.9%7D%28-20-%203x%20dx%20%29%5C%5C%5C%5CW%3D%20%5Cleft%20%5B%20-%2020%20x%20-%201.5%20x%5E2%20%5Cright%20%5D_%7B0%7D%5E%7B6.9%7D%5C%5C%5C%5CW%20%3D%20-%2020%20%286.9%20-%200%29%20-%201.5%286.9%5Ctimes%206.9%20-%200%29%5C%5C%5C%5CW%20%3D-%20138%20-%2071.42%5C%5C%5C%5CW%20%3D%20-%20209.42%20%20J)
Answer:
Work done = Force X Distance
Work done/Force = Distance
2700/560 = Distance
Distance = 4.8 meters
