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ozzi
3 years ago
7

Why is there zero current when a light bulb burns out?

Physics
1 answer:
kozerog [31]3 years ago
8 0

The circuit is no longer closed.

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The mass of a basketball is three times greater than a softball. Compare the momentum’s of a softball and a basketball if they b
ella [17]
<span>The momentum of the basketball is three times that of the softball. Momentum equals mass times velocity. Therefore, if the basketball and softball are moving at the same velocity, and the basketball has three times the mass of the softball, the basketball has three times the momentum of the softball.</span>
3 0
3 years ago
At what position in its elliptical orbit is the speed of a planet a maximum? when it is closest to the sun when it is farthest f
Phantasy [73]

Answer:

1.when it is closest to the sun

2.when it is midway between its farthest

Explanation:

According to the law of  Kepler's

T ² ∝ r³

T=Time period

r=semi major axis

We also know that time period T given as

T=\dfrac{2\pi r}{v}

v=Speed

v=\dfrac{2\pi r}{T}

v\alpha \dfrac{r}{T}

v\alpha \dfrac{r}{T}

v^2\alpha \dfrac{r^2}{T^2}

v^2\alpha \dfrac{r^2}{r^3}

v^2\alpha \dfrac{1}{r}

v\alpha \dfrac{1}{\sqrt{r}}

So we can say that ,when r is more then the speed will be minimum and when r is low then speed will be maximum.

7 0
3 years ago
When the atom's electrons step down to lower energy levels in a thin cloud of hot gas, what is produced?
Reika [66]

Answer: The correct answer is an emission line spectrum.

Explanation:

When the electrons are excited to the higher energy level, the energy is absorbed in this case.

When the electrons in the atom step down to lower energy levels in a thin cloud of hot gas then the radiation will emit.

The electron will lose energy in this case in the form of radiation. There will be an emission line spectrum.

8 0
2 years ago
Read 2 more answers
PLZZZZZZ HELP WILL MARK BRAINLEST 50 POINTS
s2008m [1.1K]

Explanation:

Earth.....Water.....Carbon

6 0
2 years ago
Which best describes the image of a concave mirror when
mr_godi [17]

Answer:

when the object goes from the focal length to twice the focal length the image goes from infinity to twice the focal length, this image is real and inverted

Explanation:

Let's use the constructor equation to describe the image of a concave mirror

    1 / f = 1 / p + 1q

where f is the focal length, p and q the distance to the object and the image, respectively

     1 /q = 1/f - 1/p

tell us that the image is between the focal and twice the focal, let's calculate the position of the image

for both ends

case 1, distance to the object       p = f

     

       1 / q = 1 / f -1 / f

       1 / q = 0

       q = ∞

    the image is in infinity

case2, distance to object p = 2f

     1 / q = 1 / f - 1 / 2f

     1 / q = 1 / 2f

     q = 2f

the image is twice the focal length, the object and the image are at the same point

therefore the image when the object goes from the focal length to twice the focal length the image goes from infinity to twice the focal length, this image is real and inverted

5 0
2 years ago
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