1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Paladinen [302]
1 year ago
9

if a Firebird travels at a velocity of 0 to 60 mph in four seconds traveling east what was the acceleration of the Firebird

Physics
1 answer:
Tresset [83]1 year ago
3 0

Answer:

6.7 m/s^2

Explanation:

The formula of acceleration is:

\displaystyle{\vec{a} = \dfrac{\Delta \vec{v}}{\Delta t} = \dfrac{v_2 - v_1}{t_2-t_1}}

where \displaystyle{\vec{a}} is acceleration, \displaystyle{\vec{v}} is velocity and \displaystyle{t} is time. \displaystyle{v_2} means final velocity. \displaystyle{v_1} means initial velocity, \displaystyle{t_2} means final time and \displaystyle{t_1} means initial time.

We are given that the Firebird travels at velocity of 0 to 60 mph in four seconds. Therefore:

  • Our initial velocity starts at 0 mph.
  • Our final velocity is at 60 mph.
  • Our initial time is 0 second.
  • Our final time is 4 seconds.

Since it travels to the east then our vector will be positive. However, acceleration has to be in m/s^2 unit (Sl unit) so we'll have to convert from mph (miles per hours) to m/s (meters per second) first.

We know that:

  • A mile equals to 1609.344 meters.
  • An hour equals to 60 minutes which a minute equals to 60 seconds. So 60 minutes will equal to 3600 seconds.

Now we divide 1609.344 by 3600 to find a unit rate of m/s:

\displaystyle{\dfrac{1609.344}{3600} \ \, \sf{m/s}}\\\\\displaystyle{= 0.44704 \ \, \sf{m/s}}

Now multiply 0.44704 m/s by 0 and 60 to get velocity in m/s unit:

  • Initial velocity = 0 m/s
  • Final velocity = 60 * 0.44704 = 26.82 m/s

Time is already in second so no need for conversion. Substitute known information in the formula:

\displaystyle{\vec{a} = \dfrac{26.82-0}{4-0}}\\\\\displaystyle{\vec{a} = \dfrac{26.82}{4}}\\\\\displaystyle{\vec{a} = 6.7 \ \, \sf{m/s^2}}

Therefore, the Firebird will accelerate at the rate of 6.7 m/s^2.

You might be interested in
If a spring has a spring constant of 1.00 × 10^3 N/m, what is the restoring force when the mass has been displaced 20.0 cm?
never [62]

The spring has a spring constant of 1.00 * 10^3 N/m and the mass has been displaced 20.0 cm then the restoring force is 20000 N/m.

Explanation:

When a spring is stretched or compressed its length changes by an amount x from its equilibrium length then the restoring force is exerted.

spring constant is k = 1.00 * 10^3 N/m

mass is x = 20.0 cm

According to Hooke's law, To find restoring force,

    F = - kx

        = - 1.00 *10 ^3 * 20.0

     F = 20000 N/m

Thus, the spring has a spring constant of 1.00 * 10^3 N/m and the mass has been displaced 20.0 cm then the restoring force is 20000 N/m.

3 0
2 years ago
Use this media to help you complete the question.
Papessa [141]

Answer:

589.3 g is the answer

Explanation:

6 0
2 years ago
At what distance along the central perpendicular axis of a uniformly charged plastic disk of radius 0.390 m is the magnitude of
aliina [53]
<span>Radius, the distance from the centre = 0.390
 Electric field is equal to half of the magnitude. E2 = E / 2
 Given
E1 = E2 E1 = k x Q / r^2
  E2 = (k x Q / r2^2) / 2
  Equating the both we get 2 x r^2 = r2^2
 r2 = square root of (2 x r1^2) = square root of (2) x r = 1.414 x 0.390
  r2 = 1.414 x 0.390 = 0.551 m</span>
3 0
3 years ago
A dandelion seed floats to the ground in a mild wind with a resultant velocity of 26.0 cm/s. If the horizontal component velocit
stira [4]

Answer:

24 cm/s

Explanation:

Applying

Pythagoras theorem,

a² = b²+c²............. Equation 1

Where a = resultant, b = vertical component, c = horizontal component

From the question,

Given: a = 26 cm/s, c = 10 cm/s

Substitute these values into equation 1

26² = b²+10²

676 = b²+100

b² = 676-100

b² = 576

b = √576

b = 24 cm/s

7 0
2 years ago
Which of the following statements are true?Check all that apply.-In a uniform electric field, the field lines are straight, para
TiliK225 [7]

Answer:

1-In a uniform electric field, the field lines are straight, parallel, and uniformly spaced this statement is true.

2-Electric field lines near positive point charges radiate outward. this statement is also true.

3-The electric force acting on a point charge is proportional to the magnitude of the point charge. this statement is true as well.

Explanation:

the electric field created by a point charge is defined by E=KQ/r^2 where k is constant, q is magnitude of charge and r is the distance away from the point charge so the electric filed is distance dependent and can not be constant at all distances.

electric field lines near a negative point charge are directed radially inward because negative charge attracts the field and is not clockwise.

6 0
3 years ago
Other questions:
  • an object 8.25 cm from a lens creates a virtual image of magnification 2.40 what is the focal length of the lens (mind your minu
    13·1 answer
  • Does wind have atoms and molecules in int
    8·1 answer
  • According to the theory of global warming, the average temperature of Earth’s air began rising rapidly when humans first started
    13·2 answers
  • Two billiard balls, each with a mass of 0.17 kg, collide with each other on a
    5·1 answer
  • If an object is not moving, what’s the net force?
    9·2 answers
  • It is well known that bullets and other missiles fired at Superman simply bounce off his chest. Suppose that a gangster sprays S
    13·1 answer
  • The soccer game begins with a ______ ______ in the center of the field
    12·1 answer
  • Gregory is visiting his grandmother, who lives 200 km from his house. While traveling there, Gregory had an average speed of 100
    9·2 answers
  • 4. Premature wrinkling due to overexposure to the Sun, what am I?​
    7·1 answer
  • A train moving at 5 m/sec passed a track gang and then accelerated uniformly a rate of 1.2 m/sec/sec for 5 min. How far did the
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!