26. An ice-skater who weighs 200 N is gliding across the ice. If the force of friction is 4 N. what is the
1 answer:
Answer:
0.02
Explanation:
coefficient of kinetic friction = μ
force of friction = Ff
Normal Force = FN, but
FN = -W
Ff = -μFN
so μ = Ff/FN
= 4N/200N
= 0.02.
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950kg. It is W=mg. therefore, mass= W/g which is W/10
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