A distant galaxy is determined to be 150 million light years distant and moving away from us; using the Hubble law determine its
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Answer:
ma = 48.48kg
Explanation:
To find the mass of the astronaut, you first calculate the mass of the chair by using the information about the period of oscillation of the empty chair and the spring constant. You use the following formula:
(1)
mc: mass of the chair
k: spring constant = 600N/m
T: period of oscillation of the chair = 0.9s
You solve the equation (1) for mc, and then you replace the values of the other parameters:
(2)
Next, you calculate the mass of the chair and astronaut by using the information about the period of the chair when the astronaut is sitting on the chair:
T': period of chair when the astronaut is sitting = 2.0s
M: mass of the astronaut plus mass of the chair = ?
(3)
Finally, the mass of the astronaut is the difference between M and mc (results from (2) and (3)) :
The mass of the astronaut is 48.48 kg
Answer:
The centripetal acceleration as a multiple of is
Explanation:
The centripetal acceleration is defined as:
(1)
Where v is the velocity and r is the radius
Since the person is standing in the Earth surfaces, their velocity will be the same of the Earth. That one can be determined by means of the orbital velocity:
(2)
Where r is the radius and T is the period.
For this case the person is standing at a latitude . Remember that the latitude is given from the equator. The configuration of this system is shown in the image below.
It is necessary to use the radius at the latitude given. That radius can be found by means of trigonometric.
(3)
Where is the radius at the latitude of
and
is the radius at the equator (
).
can be isolated from equation 3:
(4)
Then, equation 2 can be used
Notice that the period is the time that the Earth takes to give a complete revolution (24 hours), this period will be expressed in seconds for a better representation of the velocity.
⇒
Finally, equation 1 can be used:
Hence, the centripetal acceleration is
To given the centripetal acceleration as a multiple of it is gotten:
The weight of a column of air with cross-sectional area 4. 5 m^2 extending from earth's surface to the top of the atmosphere is, 4.56*10^5N.
To find the answer, we have to know about the pressure.
<h3>How to find the weight of a column of air?</h3>- As we know that the expression of pressure as,
where; F is the force, here it is equal to the weight of the air column, and A is the area of cross section.
- It is given that, the air column is extending from earth's surface to the top of the atmosphere, thus, the pressure will be atmospheric pressure,
- From this, the value of weight will be,
Thus, we can conclude that, the weight of a column of air with cross-sectional area 4. 5 m^2 extending from earth's surface to the top of the atmosphere is, 4.56*10^5N.
Learn more about the pressure here:
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