Answer:
In August 2018, NASA confirmed that M3 showed water ice is present on the surface at the Moon poles. Water was confirmed to be on the sunlit surface of the Moon by NASA on October 26, 2020.
Explanation:
Explanation:
Nitrous oxide or dinitrogen monoxide can be simple be prepared by the decomposition of ammonium nitrate in the following way -
<u>The reaction is as follows -</u>
NH₄NO₃ ----------------> N₂O + H₂O
This is the unbalanced reaction as was asked in the question , without mentioning the states of matter .
The reaction is carried out in an anhydrous condition ,since , ammonium nitrate can explode on heating .
The first step is calculating the number of HCl moles. The molar mass of HCl is AH+ACl which is 1+35,5=36,5 g/mole. The formula for the pH is -lg[H+] where [H+] is the molar concentration of protons in the solution. To find the molar concentration we need to divide the number of moles by the volume(L).
We get the number of moles by dividing the mass given in the problem to the molar mass of the compound.1.825/36.5=0.05 moles of HCl so 0.05 moles of
H+.Molarity=n/V=0.05/0.25=0.2moles/liter.The pH is -lg0.2=2.321.
<h3>
Answer:</h3>
1.6283 × 10²⁴ atoms Ni
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Reading a Periodic Table
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Stoichiometry</u>
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
158.69 g Ni
<u>Step 2: Identify Conversions</u>
Avogadro's Number
Molar Mass of Ni - 58.69 g/mol
<u>Step 3: Convert</u>
- Set up:

- Multiply/Divide:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 5 sig figs.</em>
1.62827 × 10²⁴ atoms Ni ≈ 1.6283 × 10²⁴ atoms Ni
Answer:
White phosphorusRed PhosphorusIt is insoluble in water but soluble in carbon disulphide.It is insoluble in both water and carbon disulphide.It undergoes spontaneous combustion in air.It is relatively
Explanation:
I hope it will help you