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Anuta_ua [19.1K]
3 years ago
10

Mars passes closer to earth than jupiter does, but with an earth-based telescope it is easier to see details on jupiter than on

mars. why is this?
Physics
1 answer:
nalin [4]3 years ago
6 0
Through an earth-based telescope you can see Jupiter more clearly than Mars because Jupiter is much larger than Mars and through the telescope you see the larger objects more clearly.
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Suppose that the distance an aircraft travels along a runway before takeoff is given by Upper D equals (5 divided by 3 )t square
Dahasolnce [82]

Answer:

a. Time=25seconds

b.distance=1041.67m

Explanation:

a.The equation for D in terms of m/s is \frac{250}{3}m/s after conversion.

To find when speed reaches 300km/hr=83.33m/s, we find D\prime and solve for t

D=\frac{5}{3}t^2\\D\prime=\frac{5}{3}(2t)=\frac{10}{3}t=\frac{250}{3}\\t=25sec

b. From a, above we already have our t=25seconds as the time it takes before the plane is airborne.

#To find distance travelled in that time , we substitute fort=25 in our distance equation:

D(25)=\frac{5}{3}(25)^2\\=1041.67m

Hence the distance of the plane before it gets airborne is 1041.67m

4 0
3 years ago
The number of mushrooms needed by a pizza restaurant is given by the
creativ13 [48]

Answer: 24

Explanation:

Given the following equation:

g=3n

Where g is the number of mushrooms in a pizza and n the number of pizzas.

If we know the restaurant will make 8 pizzas (n=8), then:

g=3(8)

g=24 This is the needed number of mushrooms for 8 pizzas

6 0
3 years ago
A 3.0 X 10^3 grams rock swings in a circle with a diameter of 1000 cm. Given the constant speed around the circle is 17.90 mph (
marissa [1.9K]

Answer:

a = 12.8 m/s^2

Explanation:

To find the centripetal acceleration you use the following formula:

a_c=\frac{v^2}{r}   (1)

v: tangential speed of the rock = 17.90mph

r: radius of the orbit = 1000cm/2 = 500cm = 0.5m

You first change the units of the tangential velocity in order to replace the values of v and r in the equation (1):

17.90mph*\frac{1609.34m}{1\ m}*\frac{1\ h}{3600\ s}=8m/s

Then, you use the equation (1):

a_c=\frac{(8m/s)^2}{5m}=12.8\frac{m}{s^2}

hence, the centripetal acceleration is 12.8 m/s^2

3 0
3 years ago
A box is being dragged with a horizontal force of 65 N for 12 meters. If there is a force of friction acting on it
asambeis [7]

Answer:

A. 780 J

B. 120 J

C. 660 J

Explanation:

From the question given above the following data were obtained:

Dragging force (Fₔ) = 65 N

Distance (s) = 12 m

Force of friction (Fբ) = 10 N

A. Determination of the work done by the dragging force.

Dragging force (Fₔ) = 65 N

Distance (s) = 12 m

Workdone (Wd) by dragging force =?

Wd = Fₔ × s

Wd = 65 × 12

Wd = 780 J

Therefore, the work done by the dragging force is 780 J

B. Determination of the work done by friction.

Distance (s) = 12 m

Force of friction (Fբ) = 10 N

Workdone (Wd) by friction =?

Wd = Fբ × s

Wd = 10 × 12

Wd = 120 J

Therefore, the work done by friction is 120 J

C. Determination of the net work done on the box.

Dragging force (Fₔ) = 65 N

Distance (s) = 12 m

Force of friction (Fբ) = 10 N

Net work done (Wd) =?

Next, we shall determine the net force acting on the box. This can be obtained as follow:

Dragging force (Fₔ) = 65 N

Force of friction (Fբ) = 10 N

Net force (Fₙ) =?

Fₙ = Fₔ – Fբ

Fₙ = 65 – 10

Fₙ = 55 N

Thus, the net force acting on the box is 55 N

Finally, we shall determine the net work done on the box as follow:

Distance (s) = 12 m

Net force (Fₙ) = 55 N

Net work done (Wd) =?

Wd = Fₙ × s

Wd = 55 × 12

Wd = 660 J

Therefore, the net work done on the box is 660 J

4 0
3 years ago
A motor develops 80 kW of power as it lifts a loaded elevator 20.5 m in 45 s. How much force does the motor exert? *
yuradex [85]

Answer:

F=1.3⋅105N

Explanation:

It's common knowledge.

7 0
3 years ago
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