The angular speed is decreasing and direction of rotation clockwise of the rod immediately after time t.
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</h3><h3>What is angular speed ?</h3>
The rate of change of angular displacement is defined as angular speed. It is stated as follows:
ω = θ t
Where,
θ is the angle of rotation,
t is the time
ω is the angular velocity
The torque is found as;l
If the force is acting on the rod from the three point is the same, the value of the torque is depends upon the radius or the perpendicular distance.
The perpendicular distance of the right force is grater. Hence, the force acting on the right side is more, and the rod will rotate clockwise.
Both the forces are acting downwards. Thus, the resultant force is the less due to which the speed is increasing.
Hence, the angular speed is decreasing and direction of rotation clockwise of the rod immediately after time t.
To learn more about the angular speed, refer to the link;
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Answer:
20cm
Explanation:
Hello!
remember that the condition for a body to be at rest is that the sum of its moments and its forces be zero,
To solve this problem you must draw the free body diagram of the stick (attached image) and sum up moments at point 0 (where the sharp is located), which results in the following equation
(100g)(40cm)=x(200g)
Answer:
138,516,546.9 horas.
Explanation:
Tenemos que usar la ecuación:
Velocidad = distancia/tiempo
Acá tenemos:
Velocidad = 0.3m/s
distancia = 149597870700 m
y queremos resolver la ecuación para el tiempo:
0.3m/s = 149597870700m/tiempo.
tiempo = 149597870700m/(0.3m/s) = 498,659,569,000 s
y sabemos que una hora tiene 3600 segundos, entonces si queremos transformar de segundos a horas tenemos:
498,659,569,000 s = (498,659,569,000/3600) h = 138,516,546.9 horas.
<span>b. The coefficient of static friction for all contacting surfaces is μs=0.35. neglect friction at the rollers.
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Angle, θ2 at which the light leaves mirror 2 is 56°
<u>Explanation:</u>
Given-
θ1 = 64°
So, α will also be 64°
According to the figure:
α + β = 90°
So,
β = 90° - α
= 90° - 64°
= 26°
β + γ + 120° = 180°
γ = 180° - 120° - β
γ = 180° - 120° - 26°
γ = 34°
γ + δ = 90°
δ = 90° - γ
δ = 90° - 34°
δ = 56°
According to the law of reflection,
angle of incidence = angle of reflection
θ2 = δ = 56°
Therefore, angle θ2 at which the light leaves mirror 2 is 56°
