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Alekssandra [29.7K]
3 years ago
6

The diagram illustrates the water cycle. Parts of the water cycle labeled U through Z. U: Water moving from a lake into the clou

ds. V: Clouds. W: Water falling from clouds as rain and snow. X: Water moving from ground to the clouds. Y: Water flowing down the mountainside into a lake. Z: Underground water going into lake. Which best describes the process occurring at locations U and X? Water cycles from a nonliving to a living part of the environment. Water changes from a liquid to a gas. Water changes from a gas to a liquid. Water cycles from a living to a nonliving part of the environment.
Chemistry
2 answers:
pychu [463]3 years ago
5 0

Answer:

Water changes from a liquid to a gas.

Explanation:

location U: Water moving from a lake into the clouds.

location X: Water moving from ground to the clouds

In both cases, liquid water is transformed into gas water (steam) that then rise in the sky and form clouds.

marissa [1.9K]3 years ago
4 0

The process described at locations U and X are Water changes from gas to liquid.

Answer: Option B.

<u>Explanation:</u>

Water cycle is a cyclical process when the water evaporates from the ground and then falls back on the ground in the form of rain or snow. The various stages of this process are water evaporating from lakes, ground, rivers and so on.

Then it goes up in the air, condenses. And from the condensation process, the clouds are formed. When they cool down up in the air, then the water falls back on the ground and precipitates from the cloud in the form of rain or in the form of snow.

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2 years ago
At a certain temperature, ethane has a vapor pressure of 304 torr and propane has a vapor pressure of 27 torr. What is the mole
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Answer:

166 torr

Explanation:

Let’s call ethane Component 1 and propane Component 2.

According to Raoult’s Law,  

p_{1} = \chi_{1}p_{1}^{\circ}\\p_{2} = \chi_{2}p_{2}^{\circ}

where

p₁ and p₂ are the vapour pressures of the components above the solution

χ₁ and χ₂ are the mole fractions of the components

p₁° and p₂° are the vapour pressures of the pure components.

Data:

p₁° = 304 torr

p₂° =   27 torr

n₁ = n₂

1. Calculate the mole fraction of each component

χ₁ = n₁/(n₁ + n₂)

χ₁ = n₁/n₁ + n₁)

χ₁ = n₁/(2n₁)

χ₁ = ½

χ₁ = 0.0.5

χ₂ = 1- χ₁ = 1- 0.5 = 0.5

2. Calculate the vapour pressure of the mixture

p_{1} = 0.5 \times \text{304 torr} = \text{ 152 torr}\\p_{2} = 0.5 \times \text{27 torr} = \text{ 13.5 torr}\\p_{\text{tot}} = p_{1} + p_{2} = \text{152 torr + 13.5 torr} = \textbf{166 torr}

\text{The vapour pressure above the solution is $\boxed{\textbf{166 torr}}$}

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Explanation:

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