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Zinaida [17]
3 years ago
5

If a gas sample has a pressure of 30.7 kpa at 0.00, by how many degrees celsius does the temperature have to increase to cause t

he pressure to double?
Chemistry
2 answers:
Otrada [13]3 years ago
8 0
Pressure of the gas P1 = 30.7 kpa  
When it doubled P2 = 61.4 kpa  
Temperature T1 = 0 => T1 =. 0 + 273 =273 
Temperature T2 =? 
We have pressure temperature equation P1T1 = P2T2
 => T2 = P1T1 / P2 = (30.7 x 273) / 61.4 = 136.5 
 So the temperature for doubling the pressure is 136.5.
faust18 [17]3 years ago
6 0

Answer: The temperature has to increase by 273^0C.

Explanation:

Gay-Lussac's Law: This law states that pressure is directly proportional to the temperature of the gas at constant volume and number of moles.

P\propto T     (At constant volume and number of moles)

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1 = initial pressure of gas  = 30.7 kPa

P_2 = final pressure of gas  = 2\times 30.7=61.4kPa

T_1 = initial temperature of gas  =0^0C=(0+273)K=273K

T_2 = final temperature of gas = ?

\frac{30.7}{273}=\frac{61.4}{T_2}

T_2=546K=(546-273)^0C=273^0C

Therefore, the temperature has to increase by 273^0C  to increase to cause the pressure to double.

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