Answer:
There arr 1.5*1024 molecules in 2.40 moles of H2O.
Answer:
The enthalpy change per mole of Mg is (ΔH) = 460 kj mol⁻¹
Explanation:
the total volume of the solution is
100 ml, its mass is (100 ml)(1.0 g ml⁻¹) = 100 g (Density of water 1 g ml⁻¹)
The temperature change is ΔT = 11.1 ∘C
Heat of reaction = Cs × m × ∆T
= (4.18 Jg⁻¹ ∘C⁻¹)(100 g)(11.1 ∘C)
= 4639.8 j = 4.6 kJ
Because the process occurs at constant pressure, ΔH = qP = 4.6 kJ
To express the enthalpy change on a molar basis
Mole of Mg = = 0.01 mol
Thus, the enthalpy change per mole of Mg is ΔH = = 460 kj mol⁻¹
With all of the information given (pressure, volume, temperature, and the molar mass), we need a formula that relates this all together. The formula we need is the ideal gas law, PV=nRT. Since the pressure is defined in millimeters of mercury, we need the R value that correlates with this, which is 62.4; on top of this, we need the temperature in Kelvin - simply add 273.15 to convert from Celsius. With all of this information, simply plug-and-chug:
PV=nRT
(800)(3.7) = n(62.4)(37 + 273.15)
n = 0.1529 moles
Finally, the problem is asking the amount of air in grams. We have moles, so all we need to do is multiply that value by the molar mass.
0.1529 moles x 29 grams per mole =
4.435 grams of air
The balloon has 4.435 grams of air inside it.
Hope this helps!
Answer:
Bohr diagram shows electrons orbiting the nucleus. Nitrogen has 7 electrons orbiting the nucleus
Lewis structure is the simplified Bohr diagram. It only shows the electrons in the outer shell. For Nitrogen, 2 electrons are in the first shell. The remaining 5 electrons are in the outer shell.
Explanation:
Bohr diagram shows electrons orbiting the nucleus. Nitrogen has 7 electrons orbiting the nucleus
Lewis structure is the simplified Bohr diagram. It only shows the electrons in the outer shell. For Nitrogen, 2 electrons are in the first shell. The remaining 5 electrons are in the outer shell.
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