Answer:
Work done, W = 6153.31 Joules
Explanation:
It is given that,
Weight of piano, W = F = 7382 N
It is pushed 2.16 meters friction less plank
The angle with horizontal,
When the piano slide up plank at a slow constant rate. The y component of force is taken into consideration. The net force acting on it is given by :
Work done is given by :
W = 6153.31 Joules
So, the work done in sliding the piano up the plank is 6153.31 Joules. Hence, this is the required solution.
Explanation:
It is given that,
The ramp is tilted upwards at 25 degrees and Paul is pulling a large crate up the ramp with a rope that angles 10° above the ramp.
Total angle with respect to ramp is 35 degrees.
If Paul pulls with a force of 550 N.
The horizontal component of the force is given by :
The vertical component of the force is given by :
Hence, this is the required solution.
Answer:
6840 N
Explanation:
The force acting on the car can be found by using Newton's second law:
F = ma
where
F is the net force on the car
m is the mass of the car
a is its acceleration
For the car in this problem,
m = 1800 kg
Substituting,
Answer:
The time constant is 1.049.
Explanation:
Given that,
Charge
We need to calculate the time constant
Using expression for charging in a RC circuit
Where, = time constant
Put the value into the formula
Hence, The time constant is 1.049.