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Orlov [11]
3 years ago
12

1. Consider the following equilibrium system: C(s) + CO2(g) 2CO(g)

Chemistry
1 answer:
ser-zykov [4K]3 years ago
3 0

Answer:

a) equilibrium shifts towards the right

b) equilibrium shifts towards the right

c) equilibrium shifts towards the left

d) has no effect on equilibrium position

e) has no effect on equilibrium position

Explanation:

A reversible reaction may attain equilibrium in a closed system. A chemical system is said to be in a state of dynamic equilibrium when the rate of forward reaction is equal to the rate of reaction.

According to Le Chateliers principle, when a constraint such as a change in temperature, pressure, volume or concentration is imposed upon a system in equilibrium, the equilibrium position shifts in such a way as to annul the constraint.

When the concentration of reactants is increased, the equilibrium position is shifted towards the right hand side and more products are formed. For an endothermic reaction, the reverse reaction is favoured by a decrease in temperature. Increase in pressure has no effect on the system since there are equal volumes on both sides of the reaction equation. Similarly, the addition of a catalyst has no effect on the equilibrium position since it speeds up both the forward and reverse reactions to the same extent.

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Answer:

The density is 6

Explanation:

p = m × v

p = 3 × 2

p = 6

Hope this helped! :)

8 0
3 years ago
Which of the following statements is inaccurate?
algol [13]
The inaccurate statement is C. Oxidation and reduction don't necessarily happen together, and oxidation doesn't happen first.
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3 years ago
A 2,000g of C-14 is left to decay radioactively. The half-life of Carbon-14 is approximately 5,700 years. What percentage of the
dsp73
Answer is: 12,6% (1/8) <span>percentage of the sample will remain.
</span>c₀ - initial amount of C-14.<span>
c - amount of C-14 remaining at time.
t = 5700</span> y.<span>
First calculate the radioactive decay rate constant λ:
λ = 0,693 ÷ t = 0,693 ÷ 5700</span> y = 0,000121 1/y = 1,21·10⁻⁴ y.
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4 0
3 years ago
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The partial Lewis structure that follows is for a hydrocarbon molecule. In the full Lewis structure, each carbon atom satisfies
ahrayia [7]

Answer:

C-C> C=C> C\equiv C

So, 2 > 1 > 3

Explanation:

Carbon is a  non-metal and has 6 electrons. In the excited state, it contains 4 electrons in its outermost shell and so 4 electrons take place in covalent bond formation. In a molecule , 2 carbon atoms can be bound by a single bond, the double bond and by a triple bond. Since the bond length of C\equiv C is 120 pm, the bond length of C=C is 134 pm and the bond length of C-C is 154 pm. Thus in the given compound, C= C-C\equiv C , in which C= C is labeled as 1,  C-C is labeled as 2 and C\equiv C is labeled as 3. So the bond length of carbon-carbon bonds in the molecule, in decreasing order is 2 > 1  >3.

8 0
3 years ago
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