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N76 [4]
3 years ago
9

I NEED HELP PLSS ASAP!!

Chemistry
1 answer:
goblinko [34]3 years ago
5 0

Answer:

The answer is not with me sry lol.

Explanation:

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Consider the Gibbs energies at 25 ∘ C. Substance Δ G ∘ f ( kJ ⋅ mol − 1 ) Ag + ( aq ) 77.1 Cl − ( aq ) − 131.2 AgCl
sveta [45]

Answer:

(a) +55.7 KJ/mol

(b) 1.74 x 10-10

(c) +70 KJ/mol

(d) 5.44 x 10-13

Explanation:

(a) ∆G reaction = n ∆Gproducts - m ∆Greactants

Where, = sigma = sum of,

∆ = delta = change in,

n and m = stoichiometric coefficients of the products and reactants from the balanced equation respectively.

For AgCl, it ionizes in the form:

AgCl(s) ↔ Ag+(aq) + Cl-(aq)

∆G reaction = [ {1 x ∆Gf(Ag+(aq)) } + { 1 x ∆Gf(Cl-(aq) } ] – [ { 1 x ∆Gf(AgCl(s)) } ]

∆G reaction = [ { 1 x 77.1 } + { 1 x (-131.2) } ] – [ 1 x (-109.8) ]

∆G reaction = [ 77.1 – 131.2 ] – [ -109.8 ]

∆G reaction = - 54.1 + 109.8

∆G reaction = + 55.7 KJ/mol

(b) Ksp = [Ag+] [Cl-]

At equilibrium,

∆G = -RT InK

Ksp = e (-∆G/RT)

Where, ∆G = 55.7 KJ/mol = 55.7 x 1000 J/mol = 55,700 J/mol,

R = 8.314 J/mol.K,

T = 25oC = 25 + 273.15 = 298.15 K

Ksp = e [ - 55,700 J/mol / 8.314 J/mol.K x 298.15 K ]

Ksp = e [ - 22.470 ]

Ksp = 1.74 x 10-10

(c) For AgBr, ionizing in the form:

AgBr(s) ↔ Ag+(aq) + Br-(aq)

∆G reaction = [ {1 x ∆Gf(Ag+(aq)) } + { 1 x ∆GfBr-(aq) } ] – [ { 1 x ∆Gf(AgBr(s)) } ]

∆G reaction = [ { 1 x 77.1 } + { 1 x (-104) } ] – [ 1 x (-96.9) ]

∆G reaction = [ 77.1 – 104 ] – [ -96.9 ]

∆G reaction = - 26.9 + 96.9

∆G reaction = + 70 KJ/mol

(d) Ksp = [Ag+] [Br-]

At equilibrium,

∆G = -RT InK

Ksp = e (-∆G/RT)

Where, ∆G = 70 KJ/mol = 70 x 1000 J/mol = 70,000 J/mol,

R = 8.314 J/mol.K,

T = 25oC = 25 + 273.15 = 298.15 K

Ksp = e [ - 70,000 J/mol / 8.314 J/mol.K x 298.15 K ]

Ksp = e [ - 28.2393 ]

Ksp = 5.44 x 10-13

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Phosphorus is the element among the elements given in the question that if <span>combined with chlorine, will have the greatest attraction for the chlorine electrons. The correct option among all the options given in the question is the second option or option "b" and the fact is that you have chosen correctly. </span>
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