Answer:
CaCO3----------CaO+CO2
(40g+12g+16g×3) of CaCO3 produce (40g+16g) of CaO
100g of CaCO3 -----------------56g of CaO
20g of CaCO3-------------------x grams of CaO
x=(20g×56g)÷100g
x=1120gg÷100g
x=11.2g of CaO
Therefore, 11.2grams of CaO from 20grams of CaCO3
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HCl is a monoprotic acid, which means that each mole of HCl releases one mole of hydrogen ions upon dissociation. Therefore, we calculate the moles of HCl present using:
Moles = Molarity * Volume (in liters)
Moles = 11.6 * 0.015
Moles = 0.174 moles of HCl = moles of H+ ions
Now, we use the same formula to calculate the molarity of the new solution, since the number of moles remains constant.
0.174 = M * 0.5
M = 0.348 M
The molarity of the new solution is 0.348
Question:
Which subscripts complete the chemical formula for the compound?
Answer:
A: 3
B: 8
