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SSSSS [86.1K]
3 years ago
8

DUPLICATE. The half-equivalence point of a titration occurs half way to the end point, where half of the analyte has reacted to

form its conjugate, and the other half still remains unreacted. If 0.580 moles of a monoprotic weak acid (Ka = 4.5 _ 10-5) is titrated with NaOH, what is the pH of the solution at the half-equivalence point?
Chemistry
1 answer:
Law Incorporation [45]3 years ago
5 0
At the half equivalence point [HA] = [A-] and pH = pKa 

<span>if Ka is 5.2e-5 then pKa = pH = 4.28</span>
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Identify the class of the 8 organic compound below (alcohol, carboxylic acid, halocarbon, alcohol, ketone, ester, ether). Some w
Darina [25.2K]

Answer:

See below ~

Explanation:

1) <u>Ketone</u>

2) <u>Carboxylic Acid</u>

3) <u>Ketone</u>

4) <u>Ether</u>

5) <u>Alcohol</u>

6) <u>Halocarbon</u>

7) <u>Ester</u>

8) <u>Ketone</u>

4 0
2 years ago
A student is adding DI water to a volumetric flask to make a 50% solution. Unfortunately, he was not paying attention and filled
dalvyx [7]

Answer:

His results will be skewed because there was more water than stock solution. Which would cause the percentage solution to be less than 50% therefore the density would be less than the actual value.

Explanation:

The solution will have percentage less than that of 50%. Therefore the density would be less than the actual value.

Suppose there should be 50 mL of the solution, and he added 60 mL. So 10 mL of the solution is added more.

Suppose the mass of the solute is m.

Originally, the density is = $\frac{m}{50}$     \left(\frac{\text{mass}}{\text{volume}}\right)

Now after adding extra 10 mL , the density becomes $\frac{m}{60}$.

Therefore, $\frac{m}{50}>\frac{m}{60}$

So the density decreases when we add more solution.

4 0
3 years ago
Calculate the molality of a solution containing 15.01 g of glycerol (c 3h 8o 3) in 42.3 g of ethanol (c 2h 5oh).
kkurt [141]

The molality of the glycerol solution is 3.854mol/kg

The number of moles of solute present in a solution equal to 1 kg or 1000 g of solvent is referred to as its molality.

Given:

Mass, m1 of glycerol = 15.01g

Mass, m2 of ethanol = 42.3g

Molar mass, mm1 of glycerol = 92.095g/mol

Molar mass, mm2 of ethanol = 46.069g/mol

To find:

Molality, m = ?

Formula:

Molality, m = moles of solute / kg of solvent

Calculations:

No. of moles of glycerol = 15.01 x (1/92.095)

n = 0.163 mols

Molality, m = 0.163 / 0.0423g

Molality, m = 3.854mol/kg

Result:

3.854mol/kg is the molality of the glycerol solution.

Learn more about Molality here:

brainly.com/question/26921570

#SPJ4

7 0
1 year ago
What are the products in a neutralization reaction?
aliya0001 [1]
Acid and base reactions example is: acid+base=salt+water
7 0
3 years ago
What is meant by the word chemical​
frosja888 [35]

Answer:

This is a substance that has definite composition

Explanation:

chemicals are substances that can not be broken down any further by physical process.it is a form of matter having a constant chemical characteristics and properties

5 0
3 years ago
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