A green rat snake that lives in the grass and a brown rat snake that lives in the desert is a form of what ?

1 answer:

6 0

A green rat snake that lives in the grass and a brown rat snake that lives in the desert is a form of geographically separated species.

Explanation:

The habitats of the green rat snake and brown rat snake shows that they are geographically separated species.

The two rat snakes are different species because of their distinct habitat and morphology.

When two species get separated by habitat their breeding method changes either by morphology or breeding pattern.

Such species do not produce viable offspring.

Thus a green rat snake and a brown rat snake have very different habitats they are now two different species.

Such species are said to be reproductively isolated species. Two species having genetic divergence undergo natural selection to adapt to the environment.

You might be interested in

Find change H for the reaction as it occurred in the calorimeter.

dimaraw [331]

Delta H = q / mass * delta temperature

3 0

4 years ago

. An atom of nitrogen has an atomic

GrogVix [38]

Here's the Answer !

Atomic number = no. of electrons = no. of protons, therefore :

no. of electrons = 7

no. of protons = 7

and mass number = no. of protons + no. of neutrons

so,

7 + no. of neutrons = 14

no. of neutrons = 7

5 0

3 years ago

What kind of questions do scientists ask?

Usimov [2.4K]

ones that are answered through observing :)

7 0

3 years ago

In the experiment "Beer-Lambert’s Law and Spectrophotometry", you prepared a calibration plot similar to the one pictured below.

dexar [7]

Answer:

0.025M

Explanation:

As you must see in your graph, each concentration of the experiment has an absorbance. Following the Beer-Lambert's law that states "The absorbance of a solution is directely proportional to its concentration".

At 0.35 of absorbance, the plot has a concentration of:

8 0

3 years ago

How does bond order correspond to phase? Use the drawing of MO energy diagram to predict the bond order of [Be2]+ and [Be2]−. De

erik [133]

Be2 - 1/2 is equal to be 3 over 3.4

7 0

3 years ago