Answer:
![\Delta _fS=0.2724\frac{J}{K}](https://tex.z-dn.net/?f=%5CDelta%20_fS%3D0.2724%5Cfrac%7BJ%7D%7BK%7D)
Explanation:
Hello,
In this case, we define the entropy change for such freezing process as:
![\Delta _fS=\frac{n_{Hg}\Delta _fH}{T_f}](https://tex.z-dn.net/?f=%5CDelta%20_fS%3D%5Cfrac%7Bn_%7BHg%7D%5CDelta%20_fH%7D%7BT_f%7D)
Thus, we compute the moles that are in 5.590 g of liquid mercury:
![n_{Hg}=5.590 gHg*\frac{1molHg}{200.59gHg} =0.02787molHg](https://tex.z-dn.net/?f=n_%7BHg%7D%3D5.590%20gHg%2A%5Cfrac%7B1molHg%7D%7B200.59gHg%7D%20%3D0.02787molHg)
Hence, we compute the required entropy change, considering the temperature to be in kelvins:
![\Delta _fS=\frac{0.02787mol*2.29\frac{kJ}{mol} }{(-38.9+273.15)K}\\\\\Delta _fS=2.724x10^{-4}\frac{kJ}{K} *\frac{1000J}{kJ} \\\\\Delta _fS=0.2724\frac{J}{K}](https://tex.z-dn.net/?f=%5CDelta%20_fS%3D%5Cfrac%7B0.02787mol%2A2.29%5Cfrac%7BkJ%7D%7Bmol%7D%20%7D%7B%28-38.9%2B273.15%29K%7D%5C%5C%5C%5C%5CDelta%20_fS%3D2.724x10%5E%7B-4%7D%5Cfrac%7BkJ%7D%7BK%7D%20%2A%5Cfrac%7B1000J%7D%7BkJ%7D%20%5C%5C%5C%5C%5CDelta%20_fS%3D0.2724%5Cfrac%7BJ%7D%7BK%7D)
Best regards.
Answer:
58g
Explanation:
In order to solve this problem, you must take a look at the solubility graph for potassium nitrate.
Now, the solubility graph shows you how much solute can be dissolved per 100g of water in order to make an unsaturated, a saturated, or a supersaturated solution.
You're looking to make a saturated potassium nitrate solution using
50g of water at 60∘C. Your starting point will be to determine how much potassium nitrate can be dissolved in 100g of water at that temperature in order to have a saturated solution.
As you can see, the curve itself represents saturation.
If you draw a vertical line that corresponds to 60∘C and extend it until it intersects the curve, then draw a horizontal line that connects to the vertical axis, you will find that potassium has a solubility of about
115g per 100g of water. Your answer is 58g of potassium nitrate
Answer:
83.000
Step-by-step explanation:
8.3 × 10⁴
= 8.3 × (10 × 10 × 10 × 10)
= 8.3 × (100 × 10 × 10)
= 8.3 × (100 × 100)
= 8.3 × 10.000
= 83.000
Conclusion:
The result of 8.3 × 10⁴ is 83.000
![](https://tex.z-dn.net/?f=%20)
Answer:
The field-free drift path
Explanation:
In MALDI-TOF, the sample is embedded in a matrix. A laser vaporizes the molecules in the sample with little fragmentation. The gaseous molecules are ionized, accelerated, and sent through a field-free drift path to the detector.
The proteins in the sample have different velocities based on their mass-to-charge ratio.
The fastest ions are those with the smallest m/z ratio.
The field-free drift path increases the separation between the ions, so the smallest ions reach the detector first.
Thus, the ions are separated based on their time of flight through the drift tube.
239.8 g so 240g
Explanation:
plz let me know if this is right than I can tell u how I did it :)