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garri49 [273]
3 years ago
6

What is the mass of six of these marbles? What is the volume? What is the density?

Chemistry
1 answer:
chubhunter [2.5K]3 years ago
5 0

Answer:

All right. So let's calculate the density of a glass marble. Remember that the formula for density is mass over volume. So if I know that the masses 18.5 g. And I know that the um volume is 6.45 cubic centimeters. I can go ahead and answer this to three significant figures. So it's going to be 2.87 grams per cubic centimeter. Okay, that's our density. Now, density is an intensive process. Okay. We're an intensive property. I really should say. It doesn't depend on how much you have. Mhm. If I have one marble, its density is going to be 2.87 g per cubic centimeter. If I have two marbles, the density will be the same because I'll double the mass and I'll also double the volume. So when I divide them I'll get the same number. Okay, that's what makes it an intensive property. No matter how many marbles I have, they'll have the same density. Mass though is not an intensive property. So if I have six marbles and I want to know what the massive six marbles is. Well, I know the mass of each marble is 18.5 g. So the mass of six marbles Is going to be 100 11 g. Because mass is an extensive property. It depends on how much you have. If I change the number of marbles, I'm going to change the mass. That's an extensive property. All right. So we've calculated the density. We've calculated the mass and then what happens to the density of one marble compared to six marbles as we mentioned before. Since densities and intensive property, the densities will be the same, no matter how may.

Explanation:

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Initially 10.0 mL of water was placed in a graduate cylinder and then a solid metal was immersed in the water in the graduated c
Ahat [919]

Answer: 1682 kg/m^3

Explanation:

the formula for density is mass/volume

to get the volume of the metal = Final Volume - Initial Volume

= 15.5 - 10.0 = 5.5mL

density of the metal = 9.25g/5.5mL = 1.682g/mL

to convert from g/mL to kg/m^3, multiply by 1000

density of metal = 1682 kg/m^3

7 0
3 years ago
8.<br> What behavior do all liquid<br> or plastic solids near a<br> heat source exhibit?<br> L
LuckyWell [14K]

Answer:

Explanation:

One of the properties of a liquid is that, <u>it's particles move freely (not tightly packed)</u> hence the reason for <u>it's free flowing (no definite shape)</u> when shaken in a container, unlike a solid whose <u>particles are tightly packed with restricted/no movement</u> and hence the reason for it's compactness and it's definite shape.

When a plastic solid (whose particle is tightly packed and have a restricted movement/no movement) is placed near a heat source, <u>it's particles gains energy in the process and starts to move (though slightly free) and become less tightly packed</u> hence the reason it is observed that plastic solids near a heat source melts.

From the above, it can be deduced that a liquid and a plastic solid near a heat source <u>have there particles move freely (and not tightly packed) hence making the two substances flow freely with no definite shape.</u>

7 0
3 years ago
¿Qué volumen ocuparán 12 g de hierro?
sasho [114]

Answer:

        \large\boxed{\large\boxed{volume=1.5cm^3}}

Explanation:

Translation:

  • <em>What volume will 12g of iron occupy?</em>

<em></em>

<h2>Solution</h2>

<em />

<em>Iron</em> is a solid substance at room temperature. You can find the <em>volume</em> of solids (and of not solids) using the density.

      Density=\dfrac{mass}{volume}

You can obtaindthe density of most pure substances in the internet. The density of<em> iron</em> at room temperature is 7.874 g/cm³.

Thus, substituting in the formula, you get:

      7.874g/cm^3=\dfrac{12g}{volume}\\ \\ \\ volume=\dfrac{12g}{7.874g/cm^3}\\ \\ \\ volume=1.5cm^3

The answer is rounded to two significant figures because the input, 12g, has two significant figures.

8 0
3 years ago
A nugget of gold with a mass of 521 g is added to 50.0 mL of water. The water level rises to a volume of 77.0 mL. What is the de
docker41 [41]
Displaced volume :

<span> Vf - Vi
</span>
77.0 mL - 50.0 mL => 27 mL

Therefore:

d = m / V

d = 521 / 27

d = 19.29 g/mL

6 0
3 years ago
How many molecules are in 20.2 moles of CO₂?
mrs_skeptik [129]

Answer:

1.22 x 10²⁵ molecules CO₂

Explanation:

To find the amount of molecules, you need to multiply the number of moles by Avogadro's Number. Avogadro's Number is a ratio which represents the amount of molecules per every 1 mole. It is important to arrange this ratio in a way that allows for the cancellation of units (since you are going from moles to molecules, moles should be in the denominator). The final answer should have 3 sig figs like the given value.

Avogadro's Number:

6.022 x 10²³ molecules = 1 mole

 20.2 moles CO₂           6.022 x 10²³ molecules
---------------------------  x  --------------------------------------  = 1.22 x 10²⁵ molecules
                                                     1 mole

8 0
1 year ago
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