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3 years ago

Which two things determine an object’s momentum?

Physics

2 answers:

Paul [167]3 years ago

7 0

the answer is B mass and velocity

son4ous [18]3 years ago

6 0

Momentum (in terms of classical mechanics) is defined as p = m*v, where m is the mass and v is the velocity.

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Boyle’s Law states that when a sample of gas is compressed at a constant temperature, the pressure P of the gas is inversely pro

jolli1 [7]

Answer:

a) $V=\dfrac{5.3}{P}$

b) $ML^{-4}T^{-2}$ .

Explanation:

Given that

Boyle's law

P V = Constant ,at constant temperature

Given that

$P_1=50KPa$

$V_1=0.106m^3$

We know that for PV=C

$P_1V_1=P_2V_2=PV$

Now by putting the values

PV= 50 x 0.106

$V=\dfrac{5.3}{P}$

Where P is in KPa and V is in $m^3$

PV= C

Take ln both sides

So $\ln(PV)=\ln C$

lnP + lnV =lnC ( C is constant)

By differentiating

$\dfrac{dP}{P}+\dfrac{dV}{V}=0$

$\dfrac{dP}{dV}=-\dfrac{P}{V}$

When P= 50 KPa

$\dfrac{dP}{dV}=-\dfrac{50}{V}\ \dfrac{KPa}{m^3}$

It indicates the slope of PV=C curve.

It unit is $\dfrac{Pa}{m^3}$ .

Or we can say that $ML^{-4}T^{-2}$ .

5 0

3 years ago

Read 2 more answers

Many galaxies appear to have supermassive black holes in their centers powering active galactic nuclei (also called AGN). The Sc

Lena [83]

Answer:i dont remember

Explanation: ?>>> confused

5 0

4 years ago

When operated on a household 110.0 V line, typical hair dryers draw about 1650 W of power. The current can be modeled as a long,

Andre45 [30]

Explanation:

Given that,

Voltage of household line, V = 110 V

Power of the hairdryer, P = 1650 W

During use, the current is about 1.95 cm from the user's hand.

(a) Power is given by :

$P=V\times I\\\\I=\dfrac{P}{V}\\\\I=\dfrac{1650\ W}{110\ V}\\\\I=15\ A$

(b) Again the power is given by :

$P=\dfrac{V^2}{R}$

R is resistance of the dryer

$R=\dfrac{V^2}{P}\\\\R=\dfrac{(110)^2}{1650}\\\\R=7.34\ \Omega$

(c) The magnetic field produced by the dryer at the user's hand is given by :

$B=\dfrac{\mu_o I}{2\pi r}\\\\B=\dfrac{4\pi \times 10^{-7}\times 15}{2\pi \times 1.95\times 10^{-2}}\\\\B=1.53\times 10^{-4}\ T$

Hence, this is the required solution.

4 0

3 years ago

An unbalanced force of 500 N is applied to a 75 kg object. What is the acceleration of the object?

NemiM [27]

1. Define Newtons second law of motion (this will help put things into perspective)

2.Get the mass of the object (in this case 75 kg)

3.The net force acting on the object...find it (in this case 500 N)

4.Change the equation to F=ma (500=75a)

5.Divide both sides by 75 and that is the acceleration.

7 0

3 years ago

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The electron cloud model describes which of the following?

GalinKa [24]

1. I think it's the trails left by an electron as it moves around the nucleus.

2. The atomic number is the number of protons so it is 8.

3. It's mass is lowered but it is still the same element.

3 0

3 years ago

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