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shtirl [24]
3 years ago
11

A 2.0 kg mass is lifted 4.0 m above the ground. find the change in gravitational energy

Physics
1 answer:
Makovka662 [10]3 years ago
6 0

Answer:

78.4 J

Explanation:

Given:

Mass of the object (m) = 2.0 kg

Height or displacement of the mass (h) = 4.0 m

Now, change in gravitational potential energy (ΔU) = ?

Change in gravitational potential energy of an object is the energy stored by the object when it is raised to some height above the reference ground level.

Change in gravitational potential energy of an object of mass 'm' raised to a height 'h' above the ground is given as:

\Delta U=mgh

Where, 'g' is the acceleration due to gravity and has a value of 9.8 m/s².

Now, plug in all the given values and solve for ΔU. This gives,

\Delta U=(2.0\ kg)(9.8\ m/s^2)(4.0\ m)\\\\\Delta U=78.4\ J

Therefore, the change in gravitational potential energy is 78.4 J.

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Read each question carefully. Show all your work for each part of the question. The parts within the question may not have equal weight. Spacecrafts A and B are flying parallel to each other through space and are next to each other at time t= 0. For the interval 0 <t< 6 s, spacecraft A's velocity v A and spacecraft B's velocity vB as functions of t are given by the equations va (t) = ť^2 – 5t + 20 and VB (t) = t^2+ 3t + 10, respectively, where both velocities are in units of meters per second. At t = 6 s, the spacecrafts both turn off their engines and travel at a constant speed. (a) At t = 0, is the speed of spacecraft A greater than, less than, or equal to the speed of spacecraft B?

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Answer:

<em>h = 20 m</em>

Explanation:

<u>Gravitational Potential Energy</u>

Gravitational potential energy (GPE) is the energy stored in an object due to its vertical position or height in a gravitational field.

It can be calculated with the equation:

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\displaystyle h=\frac{800}{40}=20

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