3 years ago

HELP ASAP physics projectile motion, look at the picture

1 answer:

4 0

The first answer is 0

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kumpel [21]

Answer:

$a = 5.1\ m/s^2$

Explanation:

Given,

The angle of the slide= $42^\circ$

The mass of the child is= m

coefficient of friction = 0.20

when she slides down now apply Newton's law

$ma =mg \sin\theta - f$

$ma = mg\sin \theta -\mu mg \cos \theta$

therefore the acceleration

$a=g \sin\theta -\mu gcos\theta$

$a=g[\sin \theta -\mu \cos \theta]$

$a=9.8\times [\sin 42^\circ -0.2\times \cos 42^\circ]$

$a = 5.1\ m/s^2$

hence, the magnitude of acceleration during her sliding is equal to $a = 5.1\ m/s^2$

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3 years ago

GREYUIT [131]

13680000 should be the number of seconds

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3 years ago

____ [38]

The correct answer is answer choice B.

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3 years ago

sasho [114]

7000 N / 0,4m^2 = 17 500 Pa.

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Firlakuza [10]

La ce materie vr ca sunt pe tableta

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3 years ago