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gavmur [86]
3 years ago
12

HELP ASAP physics projectile motion, look at the picture

Physics
1 answer:
fiasKO [112]3 years ago
4 0
The first answer is 0
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186282 miles. Hope it helps

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3. Magnetite is <br>a) Natural magnet <br>(b)Artificial magnet <br>(c) Not a magnet ​
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<em>Magnetite is a Natural magnet</em>

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2 years ago
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WILL GIVE BRAINLIEST HELP FASTWhat is the mass of Planet X? Note: The constant of universal gravity (G) equals 6.674 X 10-11 N·m
disa [49]

Answer:

Explanation:

Centripetal acceleration's equation is:

a_c=\frac{v^2}{r} where v is the velocity of the object (moon II) and r is the radius. We have the radius, but we don't have the velocity, and we can't solve for acceleration until we do have it. Assuming moon II is a circle, or close enough to be called a circle, it has a circumference.

C = 2πr. If we can find the circumference of the circle, we can plug in the orbital period for the time, the circumference for the distance, and solve for velocity in d = rt. So let's do that and see what happens.

C = 2(3.14)(9.0 × 10⁷) and

C = d = 5.7 × 10⁸. Plugging in and solving for v:

5.7*10^8=v(3.0*10^5) and

v = 1.9 × 10³. That is the velocity we can use in the centripetal acceleration equation.

a_c=\frac{(1.9*10^3)^2}{9.0*10^7} and

a_c=.040\frac{m}{s^2}

These are fun!

8 0
2 years ago
A train moving at a constant speed of 50.0 km/h moves east for 45.0 min, then in a direction 45.0° east of due north for 10.0 mi
Yuki888 [10]

Answer:

3.47km/h with a direction of 67.8 degrees north of west.

Explanation:

First we need to calculate the displacement on the X axis, so:

d_{x1}=50.0km/h*45min(\frac{1h}{60min})=37.5km\\d_{x2}=50.0km/h*10min(\frac{1h}{60min})*cos(45^o)=5.90km\\d_{x1}=-50.0km/h*55.0min(\frac{1h}{60min})=45.8km\\D_x=37.5+5.90-45.8=-2.4km

then on the Y axis:

D_y=50.0km/h*10min(\frac{1h}{60min})*sin(45^o)=5.90km

The magnitud of the displacement is given by:

D=\sqrt{D_x^2+D_y^2} \\D=6.37km

and the angle:

\alpha =arctg(\frac{5.90}{2.41})=67.8^o

that is 67.8 degrees north of west.

v=\frac{D}{t}\\v=\frac{6.37km}{110min*\frac{1h}{60min}}\\v=3.47km/h

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3 years ago
How much current is running through a circuit powered by a 1.5 volt battery wit 18
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