HELP ASAP physics projectile motion, look at the picture

The force of attraction between two oppositely charged pith is 5mx 10 to the -6th power newtons. If the charge on the two is 6.7

My name is Ann [436]

Answer:

0.28 m

Explanation:

The following data were obtained from the question:

Force (F) = 5×10¯⁶ N

Charge 1 (q₁) = 6.7×10¯⁹ C

Charge 2 (q₂) = 6.7×10¯⁹ C

Electrical constant (K) = 9×10⁹ Nm²C¯²

Distance apart (r) =?

Thus, the distance between the two charges can be obtained as follow:

F = Kq₁q₂/r²

5×10¯⁶ = 9×10⁹ × 6.7×10¯⁹ × 6.7×10¯⁹/r²

5×10¯⁶ = 4.0401×10¯⁷ / r²

Cross multiply

5×10¯⁶ × r² = 4.0401×10¯⁷

Divide both side by 5×10¯⁶

r² = 4.0401×10¯⁷ / 5×10¯⁶

Take the square root of both side

r = √(4.0401×10¯⁷ / 5×10¯⁶)

r = 0.28 m

Therefore, the distance between the two charges is 0.28 m

4 0

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Some of the quantities you measure in this lab are vectors and some are scalers. When you add vectors together youneed to worry

GalinKa [24]

Answer:

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Explanation:

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PilotLPTM [1.2K]

Answer:

Mass and Acceleration

Explanation:

The typical Force equation is:

F = ma

where m = mass, and a=acceleration.

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3 years ago

Read 2 more answers

| A T-ball with a mass of 0.6 kg travels in the

r-ruslan [8.4K]

Answer:

$|I|=6\ Kg.m/s$

$F=120\ N$

Explanation:

Impulse and Momentum

They are similar concepts since they deal with the dynamics of objects having their status of motion changed by the sudden application of a force. The momentum at a given initial time is computed as

$p_o=m.v_o$

When a force is applied, the speed changes to $v_1$ and the new momentum is

$p_1=m.v_1$

The change of momentum is

$\Delta p=p_1-p_0=m(v_1-v_o)$

The impulse is equal to the change of momentum of an object and it's defined as the average net force applied times the time it takes to change the object's motion

$I=F.t=\Delta p$