Answer:
0.28 m
Explanation:
The following data were obtained from the question:
Force (F) = 5×10¯⁶ N
Charge 1 (q₁) = 6.7×10¯⁹ C
Charge 2 (q₂) = 6.7×10¯⁹ C 
Electrical constant (K) = 9×10⁹ Nm²C¯²
Distance apart (r) =?
Thus, the distance between the two charges can be obtained as follow:
F = Kq₁q₂/r²
5×10¯⁶ = 9×10⁹ × 6.7×10¯⁹ × 6.7×10¯⁹/r²
5×10¯⁶ = 4.0401×10¯⁷ / r²
Cross multiply 
5×10¯⁶ × r² = 4.0401×10¯⁷
Divide both side by 5×10¯⁶
r² = 4.0401×10¯⁷ / 5×10¯⁶ 
Take the square root of both side 
r = √(4.0401×10¯⁷ / 5×10¯⁶)
r = 0.28 m
Therefore, the distance between the two charges is 0.28 m
 
        
             
        
        
        
Answer:
Mass and Acceleration
Explanation:
The typical Force equation is:
F = ma
where m = mass, and a=acceleration.
 
        
                    
             
        
        
        
Answer:


Explanation:
Impulse and Momentum
They are similar concepts since they deal with the dynamics of objects having their status of motion changed by the sudden application of a force. The momentum at a given initial time is computed as

When a force is applied, the speed changes to  and the new momentum is
 and the new momentum is

The change of momentum is

The impulse is equal to the change of momentum of an object and it's defined as the average net force applied times the time it takes to change the object's motion

Part 1
The T-ball initially travels at 10 m/s and then suddenly it's stopped by the glove. The final speed is zero, so

The impulse is


The magnitude is

Part 2
The force can be computed from the formula

The direction of the impulse the T-ball receives is opposite to the direction of the force exerted by the ball on the glove, thus 

