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mr Goodwill [35]
3 years ago
13

Which of the following is true about two neutral atoms of the element zinc?

Chemistry
2 answers:
Ymorist [56]3 years ago
8 0
It isn't specified which neutral atom of zinc it pertains to. There are 5 stable isotopes of Zinc. It could be any of those. However, one thing is true for all possible conditions. These neutral atoms would have the same number of protons because they are of the Zinc element. It would always have 30 protons when neutral. So, the answer is: <span><em>Both have an equal number of protons.</em></span>
uysha [10]3 years ago
6 0

C) Both have an equal number of protons

please mark me brainliest :)


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<u>Answer:</u>

<u>For a:</u> The equilibrium mixture contains primarily reactants.

<u>For b:</u> The equilibrium mixture contains primarily products.

<u>Explanation:</u>

There are 3 conditions:

  • When K_{eq}>1; the reaction is product favored.
  • When K_{eq}; the reaction is reactant favored.
  • When K_{e}=1; the reaction is in equilibrium.

For the given chemical reactions:

  • <u>For a:</u>

The chemical equation follows:

HCN(aq.)+H_2O(l)\rightleftharpoons CN^-(aq.)+H_3O^+(aq.);K_{eq}=6.2\times 10^{-10}

The expression of K_{eq} for above reaction follows:

K_{eq}=\frac{[CN^-][H_3O^+]}{[HCN][H_2O]}=6.2\times 10^{-10}

As, K_{eq}, the reaction will be favored on the reactant side.

Hence, the equilibrium mixture contains primarily reactants.

  • <u>For b:</u>

The chemical equation follows:

H_2(g)+Cl_2(g)\rightleftharpoons 2HCl(g);K_{eq}=2.51\times 10^{4}

The expression of K_{eq} for above reaction follows:

K_{eq}=\frac{[HCl]^2}{[H_2][Cl_2]}=2.51\times 10^{4}

As, K_{eq}>1, the reaction will be favored on the product side.

Hence, the equilibrium mixture contains primarily products.

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