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2 years ago

A chef fills a 50 mL container with 43.5 g of cooking oil. What is the density of the oil?

Chemistry

2 answers:

Shalnov [3]2 years ago

6 0

Answer:

.87

Explanation:

Density is a mass divided by volume

olga_2 [115]2 years ago

3 0

Denisty(d) is described by formula :

d = m / V

where m is mass and V is volume

m = 43.5 g

V = 50 mL

d = 43.5 g / 50 mL = 0.87 g/mL

Answer : Density of this cooking oil is 0.87 g/mL.

(-_-(-_-)-_-)

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2 years ago

A sample of xenon gas occupies a volume of 6.80 L at 52.0°C and 1.05 atm. If it is desired to increase the volume of the gas sam

Pavlova-9 [17]

Answer:

207.03°C

Explanation:

The following data were obtained from the question:

V1 (initial volume) = 6.80 L

T1 (initial temperature) = 52.0°C = 52 + 273 = 325K

P1 (initial pressure) = 1.05 atm

V2 (final volume) = 7.87 L

P2 (final pressure) = 1.34 atm

T2(final temperature) =?

Using the general gas equation P1V1/T1 = P2V2/T2, the final temperature of the gas sample can be obtained as follow:

P1V1/T1 = P2V2/T2

1.05 x 6.8/325 = 1.34 x 7.87/T2

Cross multiply to express in linear form as shown below:

1.05 x 6.8 x T2 = 325 x 1.34 x 7.87

Divide both side by 1.05 x 6.8

T2 = (325 x 1.34 x 7.87) /(1.05 x 6.8)

T2 = 480.03K

Now, let us convert 480.03K to a number in celsius scale. This is illustrated below:

°C = K - 273

°C = 480.03 - 273

°C = 207.03°C

Therefore, the final temperature of the gas will be 207.03°C

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