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velikii [3]
3 years ago
5

Which statement about astrology is not true?

Physics
2 answers:
Brrunno [24]3 years ago
5 0
A. planets do not affect birth defects
sweet-ann [11.9K]3 years ago
5 0

Answer:

C. Astrology made contributions to the science of astronomy.

Explanation:

Astrology is predicting the future or personality of someone basis their zodiac signs and the positions of celestial objects at the time of their birth. It is not based on latest facts of astronomy and doesn't take the change in the state of celestial objects in their prediction.

That is why it is called a pseudoscience. It has not contributed in the science of Astronomy. In fact the astrologers used the findings of astronomy to crate this pseudoscience. That is why statement 3 is not true about astrology.

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390kJ

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What clouds are best associated with thunderstorms?
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Cumulus Congestus & Cumulonimbus Clouds

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Which are the products in the equation CH3SH + 4O2 → CO2 + SO2 +2H2O? Check all that apply. CH3SH, O2 ,CO2, SO2, H2O
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Read 2 more answers
What type of wave has more energy, an ultraviolet wave or an x-ray?
muminat
As the wave length increases the energy of the wave decreases as the equation that relates the c=λυ λ is the wave length and υ is the frequency (which is directly proportional to the energy).
In the wave length spectrum, x-ray has a shorter wave length, meaning that x-ray has a higher energy than ultraviolet waves.

Hope this helps.

3 0
2 years ago
Three forces act on a moving object. One force has a magnitude of 83.7 N and is directed due north. Another has a magnitude of 5
LekaFEV [45]

Answer:

  • |\vec{F}_3| = 102.92 \ N
  • \theta = 57 \° 24 ' 48''

Explanation:

For an object to move with constant velocity, the acceleration of the object must be zero:

\vec{a} = \vec{0}.

As the net force equals acceleration multiplied by mass , this must mean:

\vec{F}_{net} = m \vec{a} = m * \vec{0} = \vec{0}.

So, the sum of the three forces must be zero:

\vec{F}_1 + \vec{F}_2 + \vec{F}_3 = \vec{0},

this implies:

\vec{F}_3  = - \vec{F}_1 - \vec{F}_2.

To obtain this sum, its easier to work in Cartesian representation.

First we need to define an Frame of reference. Lets put the x axis unit vector \hat{i} pointing east,  with the y axis unit vector \hat{j} pointing south, so the positive angle is south of east. For this, we got for the first force:

\vec{F}_1 = 83.7 \ N \ (-\hat{j}),

as is pointing north, and for the second force:

\vec{F}_2 = 59.9 \ N \ (-\hat{i}),

as is pointing west.

Now, our third force will be:

\vec{F}_3  = - 83.7 \ N \ (-\hat{j}) - 59.9 \ N \ (-\hat{i})

\vec{F}_3  =  83.7 \ N \ \hat{j}  + 59.9 \ N \ \hat{i}

\vec{F}_3  =  (59.9 \ N , 83.7 \ N )

But, we need the magnitude and the direction.

To find the magnitude, we can use the Pythagorean theorem.

|\vec{R}| = \sqrt{R_x^2 + R_y^2}

|\vec{F}_3| = \sqrt{(59.9 \ N)^2 + (83.7 \ N)^2}

|\vec{F}_3| = 102.92 \ N

this is the magnitude.

To find the direction, we can use:

\theta = arctan(\frac{F_{3_y}}{F_{3_x}})

\theta = arctan(\frac{83.7 \ N }{ 59.9 \ N })

\theta = 57 \° 24 ' 48''

and this is the angle south of east.

7 0
2 years ago
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