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s344n2d4d5 [400]
2 years ago
10

Which line represents an object that is in motion where the acceleration is zero and the velocity is to the north?

Physics
1 answer:
Alex787 [66]2 years ago
3 0

Answer:

what do the lines look like

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Find the average speed of a walk to school and back if you took 12 minutes to walk there and 18 minutes to get back
nikdorinn [45]

Answer:

12+ 18 divide by 2 is the average minutes

7 0
2 years ago
Onur drops a basketball from a height of 10m on Mars, where the acceleration due to gravity has a magnitude of 3.7m/s2.​ We want
lbvjy [14]

Explanation:

It is given that, Onur drops a basketball from a height of 10 m on Mars, where the acceleration due to gravity has a magnitude of 3.7 m/s².

The second equation of kinematics gives the relationship between the height reached and time taken by it.

Here, the ball is droped under the action of gravity. The value of acceleration due to gravity on Mars is positive.

We want to know how many seconds the basketball is in the air before it hits the ground. So, the formula is :

\Delta x=v_ot+\dfrac{1}{2}at^2

t is time taken by the ball to hit the ground

v_o is initial speed of the ball

So, the correct option is (A).

8 0
3 years ago
A computer disk drive is turned on starting from rest and has a constant angular acceleration. If it took 0.750 seconds for the
Irina-Kira [14]

Answer:

a) Θ = ω₀*t + ½αt² To complete first revolution 2π rads = 0*t + ½αt² and to complete the first and second combined 4π rads = 0*t + ½α(t+0.810s)² Divide second by first: 2 = (t + 0.810s)² / t² This is quadratic in t and has roots at t = -0.336 s ← ignore and t = 1.96 s ◄ b) Use either equation from above: 2π rads = 0*t + ½α(1.96s)² α = 3.27 rad/s² ◄ Hope this helps!

Explanation:

6 0
3 years ago
Scenario A: A 3 spring is compressed a distance of 1.0 m. Scenario B: A 6 spring is compressed a distance of 0.8 m. Scenario C:
lapo4ka [179]

The CORRECT answer is B

6 0
3 years ago
Read 2 more answers
A person in a boat sees a fish in the water (n = 1.33, the light rays making an angle of 40? relative to the water's surface. wh
jek_recluse [69]
We know that the measure of an incident ray is:  α 1 = 40°.
The index of refraction:
- for the air : n 1 = 1.00,
- for the water: n 2 = 1.33
Snell`s Law of Refraction :
n 1 · sin α 1 = n 2 · sin α 2
sin α 2 = n 1 · sin α 1 / n 2 =
= 1.00 · sin 40° / 1.33 = 0.64278 / 1.33 = 0.4833
α 2 = sin ^(-1) 0.4833
α 2 = 28.9 °
Answer: The angle relative to the water`s surface of the rays when beneath the surface is 28.9°.

4 0
3 years ago
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