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AnnZ [28]
3 years ago
6

Determine the molarity for each of the following Solution: 98.0 of phosphoric acids H3PO4 in 1.00L of Solution.​

Chemistry
1 answer:
Rufina [12.5K]3 years ago
8 0

The molarity of the solution is 0.01.

Brainliest?

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Condensation-the process by which water vapor in the air is changed into liquid water.
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At the end of β-oxidation all carbons of a fatty acid are released in the form of
user100 [1]

Answer:

ACETYL-CoA, FADH

2  NADH  

 acetyl-CoA

Explanation: Beta oxidation of carbons of fatty acid acid molecules leads to the formation Acetyl-CoA, FADH and NADH.

The overall reaction for the process

Cn-acyl-CoA + FAD + NAD+

+ H

2O + CoA → Cn-2-acyl-CoA + FADH

2 + NADH + H+

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formula of NADH is C21H27N7O14P2

formula of FADH is ‎C27H35N9O15P2.

Both NADH(Nicotinamide adenine dinucleotide) and FADH( Flavin adenine dinucleotide) are

formular for Acetyl CoA IS C23H38N7O17P3S.

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4 0
3 years ago
If a gas occupies 79.5 mL at -1.4°C, what temperature, in Kelvin, would it
Anna35 [415]

Answer:

121 K

Explanation:

Step 1: Given data

  • Initial volume (V₁): 79.5 mL
  • Initial temperature (T₁): -1.4°C
  • Final volume (V₂): 35.3 mL

Step 2: Convert "-1.4°C" to Kelvin

We will use the following expression.

K = °C + 273.15 = -1.4°C + 273.15 = 271.8 K

Step 3: Calculate the final temperature of the gas (T₂)

Assuming ideal behavior and constant pressure, we can calculate the final temperature of the gas using Charles' law.

V₁/T₁ = V₂/T₂

T₂ = V₂ × T₁/V₁

T₂ = 35.3 mL × 271.8 K/79.5 mL = 121 K

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Kind of protists can live in groups with different individuals performing different jobs (site 1)
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The plasmodial slime molds are the kind of protist that can live in groups in which different individuals perform different jobs. Some kinds of bacterial cell walls also have other functions.

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