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3 years ago

Select the correct difference.

Mathematics

2 answers:

scZoUnD [109]3 years ago

5 0

Answer: First option is correct.

Step-by-step explanation:

Since we have given that

$5d^2+4d-3-(2d^2-3d+4)$

We need to find the correct difference.

Collect the like terms together.

$5d^2+4d-3-(2d^2-3d+4)\\\\=5d^2+4d-3-2d^2+3d-4\\\\=5d^2-2d^2+4d+3d-3-4\\\\=3d^2+7d-7$

Hence, First option is correct.

Zinaida [17]3 years ago

4 0

Answer:

Option (a) is correct.

$5d^2+4d-3-(2d^2-3d+4)=3d^2+7d-7$

Step-by-step explanation:

Given: $5d^2+4d-3-(2d^2-3d+4)$

We have to solve the given expression and choose the correct difference from the given options.

Consider the given expression $5d^2+4d-3-(2d^2-3d+4)$

Apply plus- minus rule, $-(-a)=a$

We have,

$=5d^2+4d-3-2d^2+3d-4$

Adding like terms, we have,

LIKE TERMS are terms having same variable with same degree.

$=(5-2)d^2+(4+3)d-(3+4)$

Simplify, we have,

$=3d^2+7d-7$

Thus, Option (a) is correct.

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3 years ago

48 is the product of Carlos's age and 3.

Sergio [31]

Answer:

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3 years ago

−6x−3(x−2) PLEASE HELP

vodomira [7]

Answer:

-9x + 6

Step-by-step explanation:

-6x−3(x−2)

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5 0

3 years ago

The augmented matrix of a system of equations has been transformed to an equivalent matrix inâ€‹ row-echelon form. Usingâ€‹ x, y

jenyasd209 [6]

Answer: The system of equations is:

x + 2y + 2 = 4

y - 3z = 9

z = - 2

The solution is: x = -22; y = 15; z = -2;

Step-by-step explanation: ONe way of solving a system of equations is using the Gauss-Jordan Elimination.

The method consists in transforming the system into an augmented matrix, which is writing the system in form of a matrix and then into a Row Echelon Form, which satisfies the following conditions:

There is a row of all zeros at the bottom of the matrix;
The first non-zero element of any row is 1, which called leading role;
The leading row of the first row is to the right of the leading role of the previous row;

For this question, the matrix is a Row Echelon Form and is written as:

$\left[\begin{array}{ccc}1&2&2\\0&1&3\\0&0&1\end{array}\right]$ $\left[\begin{array}{ccc}4\\9\\-2\end{array}\right]$

or in system form:

x + 2y + 2z = 4

y + 3z = 9

z = -2

Now, to determine the variables:

z = -2

y + 3(-2) = 9

y = 15

x + 30 - 4 = 4

x = - 22

The solution is (-22,15,-2).

4 0

3 years ago

Where does the normal line to the parabola y = x − x2 at the point (1, 0) intersect the parabola a second time?

Ksivusya [100]

Find the line that is normal to the parabola at the given point
remember that normal means perpendicular
perpendicular lines have slopes that multiply to -1
we can use point slope form to write the equation of the line since we are given the point (1,0)

we just need the slope

take derivitive
y'=1-2x
at x=1
y'=1-2(1)
y'=1-2
y'=-1

the slope is -1
the perpendicular of that slope is what number we can multiply to get -1
-1 times what=-1?
what=1
duh
so
point (1,0) and slope 1
y-0=1(x-1)
y=x-1 is da equation

solve for where y=x-1 and y=x-x² intersect

set equatl to each other since equal y
x-1=x-x²
x²-1=0
factor difference of 2 perfect squares
(x-1)(x+1)=0
set to zero

x-1=0
x=1
we got this point already

x+1=0
x=-1
sub back
y=-1-(-1)²
y=-1-(1)
y=-1-1
y=-2

it intersects at (-1,-2)

7 0

3 years ago