<u>Answer:</u> The molar mass of the insulin is 6087.2 g/mol
<u>Explanation:</u>
To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

Or,

where,
= osmotic pressure of the solution = 15.5 mmHg
i = Van't hoff factor = 1 (for non-electrolytes)
Mass of solute (insulin) = 33 mg = 0.033 g (Conversion factor: 1 g = 1000 mg)
Volume of solution = 6.5 mL
R = Gas constant = 
T = temperature of the solution = ![25^oC=[273+25]=298K](https://tex.z-dn.net/?f=25%5EoC%3D%5B273%2B25%5D%3D298K)
Putting values in above equation, we get:

Hence, the molar mass of the insulin is 6087.2 g/mol
the god ran down the street
Answer:
H2 + I2 --> 2HI
Explanation:
The two reactants are diatomic molecules because they contain two atoms of the same element. Therefore, they would need to have a subscript of "2" next to their symbols.
When balancing an equation, you want the same amount and type of atoms on both sides. By adding a coefficient of "2" in front of the product, two H's and two I's are now on both sides.
Nuetrons+protons. and number 7 is electrons and protons
A 0.9621 g sample, whose mass percent of hydrogen peroxide is 1.17% requires 11.07 mL of 0.0200 M KMnO₄ to react completely.
Let's consider the balanced equation for the reaction between H₂O₂ and KMnO₄.
2 KMnO₄ + 3 H₂O₂ → 3 O₂ + 2 MnO₂ + 2 KOH + 2 H₂O
11.07 mL of 0.0200 M KMnO₄ react. We can calculate the reacting mass of H₂O₂ considering that:
- The molar ratio of KMnO₄ to H₂O₂ is 2:3.
- The molar mass of H₂O₂ is 34.01 g/mol.

0.0113 g of H₂O₂ are in 0.9621 g of the sample. The mass percent of H₂O₂ in the sample is:

A 0.9621 g sample, whose mass percent of hydrogen peroxide is 1.17% requires 11.07 mL of 0.0200 M KMnO₄ to react completely.
Learn more: brainly.com/question/9743981