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aalyn [17]
3 years ago
13

how does getting funding from the government affect scientific research?? a- the government helps the scientist decide what rese

arch is important b- the government tells the scientist what research they can do c-scientist can only do research that helps the government protect its citizens d- scientist have to follow government rules made to protect people
Chemistry
1 answer:
sertanlavr [38]3 years ago
4 0

Answer:

d- Scientists have to follow government rules made to protect people.

Explanation:

Scientific research fosters our understanding of the world around us. It helps people to learn to promote critical thought and problem-solving.  Although there may not be an immediate practical use of the research, in the long term the study could benefit humanity. Scientific research is the product of creative ideas and collaborative communication that the proper role of government is often restricted to funding the research. The role of the government is to perform its reasonable and valid duties of defending human rights and enhancing the independence of the human.

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A solution made by dissolving 33 mg of insulin in 6.5 mL of water has an osmotic pressure of 15.5 mmHg at 25°C. Calculate the mo
Liula [17]

<u>Answer:</u> The molar mass of the insulin is 6087.2 g/mol

<u>Explanation:</u>

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

\pi=iMRT

Or,

\pi=i\times \frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}\times RT

where,

\pi = osmotic pressure of the solution = 15.5 mmHg

i = Van't hoff factor = 1 (for non-electrolytes)

Mass of solute (insulin) = 33 mg = 0.033 g   (Conversion factor: 1 g = 1000 mg)

Volume of solution = 6.5 mL

R = Gas constant = 62.364\text{ L.mmHg }mol^{-1}K^{-1}

T = temperature of the solution = 25^oC=[273+25]=298K

Putting values in above equation, we get:

15.5mmHg=1\times \frac{0.033\times 1000}{\text{Molar mass of insulin}\times 6.5}\times 62.364\text{ L.mmHg }mol^{-1}K^{-1}\times 298K\\\\\text{molar mass of insulin}=\frac{1\times 0.033\times 1000\times 62.364\times 298}{15.5\times 6.5}=6087.2g/mol

Hence, the molar mass of the insulin is 6087.2 g/mol

8 0
3 years ago
8.7g+15.43g+19g?<br> 853.2L-627.443L?<br> 5.47m+11m+87.300m?
gizmo_the_mogwai [7]

the god ran down the street

6 0
3 years ago
Consider the following unbalanced particulate representation of a chemical equation:
nevsk [136]

Answer:

H2 + I2 --> 2HI

Explanation:

The two reactants are diatomic molecules because they contain two atoms of the same element. Therefore, they would need to have a subscript of "2" next to their symbols.

When balancing an equation, you want the same amount and type of atoms on both sides. By adding a coefficient of "2" in front of the product, two H's and two I's are now on both sides.

3 0
3 years ago
I need help with number 8 and fast it's due tomorrow. :)
EastWind [94]
Nuetrons+protons. and number 7 is electrons and protons
3 0
3 years ago
For the reaction, a 0.9621 g sample of an unknown aqueous hydrogen peroxide solution required 11.07 mL of 0.0200 M KMnO4. Calcul
hichkok12 [17]

A 0.9621 g sample, whose mass percent of hydrogen peroxide is 1.17% requires 11.07 mL of 0.0200 M KMnO₄ to react completely.

Let's consider the balanced equation for the reaction between H₂O₂ and KMnO₄.

2 KMnO₄ + 3 H₂O₂ → 3 O₂ + 2 MnO₂ + 2 KOH + 2 H₂O

11.07 mL of 0.0200 M KMnO₄ react. We can calculate the reacting mass of H₂O₂ considering that:

  • The molar ratio of KMnO₄ to H₂O₂ is 2:3.
  • The molar mass of H₂O₂ is 34.01 g/mol.

0.01107L\ KMnO_4 \times \frac{0.0200mol KMnO_4}{1L\ KMnO_4} \times \frac{3molH_2O_2}{2molKMnO_4}  \times \frac{34.01gH_2O_2}{1molH_2O_2} =0.0113gH_2O_2

0.0113 g of H₂O₂ are in 0.9621 g of the sample. The mass percent of H₂O₂ in the sample is:

\% H_2O_2 = \frac{0.0113g}{0.9621g} \times 100\% = 1.17\%

A 0.9621 g sample, whose mass percent of hydrogen peroxide is 1.17% requires 11.07 mL of 0.0200 M KMnO₄ to react completely.

Learn more: brainly.com/question/9743981

7 0
3 years ago
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