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Reil [10]
4 years ago
14

What affects sounds at their source

Physics
1 answer:
zheka24 [161]4 years ago
4 0

Answer:

that's called Doppler effect

Explanation:

its observed because the distance between the source of sound and the observer is changing. If the source and the observer are approaching, then the distance is decreasing and if the source and the observer are receding.

-Hops

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What is the test for whether or not a moving object is in equilibrium?
Sphinxa [80]

It is in equilibrium if its velocity is not changing.

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3 years ago
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A stretched spring has 5184 J of elastic potential energy and a spring constant of 16,200 N/m. What is the displacement of the s
Ira Lisetskai [31]
The elastic potential energy (Ep) is given by Ep =  \frac{1}{2}*k*x^2

Data:
Ep = 5184 J
k = 16200 N/m
x (displacement) = ?

Solving:
Ep = \frac{1}{2}*k*x^2
5184 = \frac{1}{2}*16200*x^2
5184*2 = 16200x^2
10368 = 16200x^2
16200x^2 = 10368
x^2 =  \frac{10638}{16200}
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\boxed{\boxed{x = 0.8\:m}}\end{array}}\qquad\quad\checkmark

8 0
4 years ago
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A hydraulic system uses a(n) ____________________ to transmit pressure.
frosja888 [35]
The answer would be transducers
4 0
4 years ago
Apollo 14 astronaut Alan B. Shepard Jr. used an improvised six-iron to strike two golf balls while on the Fra Mauro region of th
Illusion [34]

Complete Question

Apollo 14 astronaut Alan B. Shepard Jr. used an improvised six-iron to strike two golf balls while on the Fra Mauro region of the moon’s surface, making what some consider the longest golf drive in history. Assume one of the golf balls was struck with initial velocity v0 = 32.75 m/s at an angle θ = 32° above the horizontal. The gravitational acceleration on the moon’s surface is approximately 1/6 that on the earth’s surface. Use a Cartesian coordinate system with the origin at the ball's initial position.

Randomized Variables

vo 32.75 m/s

theta 32 degrees

What horizontal distance, R in meters, did this golf ball travel before returning to the lunar surface?

Answer:

The  horizontal distance is  R =  590.2 \ m  

Explanation:

From the question we are told that

 The initial  velocity is  v_o =  32.75 \  m/s

  The angle is  \theta =  26^o

  The gravitational acceleration of the moon is g_m  =  \frac{1}{6}  *  9.8   = 1.633 m/s^2

 Generally the distance traveled is mathematically represented as

    R =  \frac{v_o^2 sin 2(\theta)}{g_m}

=> R =  \frac{32.75^2 sin 2(32)}{1.633}

=> R =  590.2 \ m  

             

8 0
3 years ago
A Venturi tube may be used as a fluid flowmeter. Suppose the device is used at a service station to measure the flow rate of gas
leonid [27]

Answer

given,

flow rate = p = 660 kg/m³

outer radius = 2.8 cm

P₁ - P₂ = 1.20 k Pa

inlet radius = 1.40 cm

using continuity equation

 A₁ v₁ = A₂ v₂

 π r₁² v₁ = π r₁² v₂

 v_1= \dfrac{r_1^2}{r_2^2} v_2

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Applying Bernoulli's equation

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 \Delta P = \dfrac{1}{2}\rho v_2^2 (1 - 0.0625)

 v_2=\sqrt{\dfrac{2\Delta P}{\rho(1 - 0.0625)}}

 v_2=\sqrt{\dfrac{2\times 1200}{660 \times(1 - 0.0625)}}

       v₂ = 1.97 m/s

b) fluid flow rate

Q = A₂ V₂

Q = π (0.014)²  x 1.97

Q = 1.21 x 10⁻³ m³/s

5 0
3 years ago
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