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Ann [662]
3 years ago
11

Check all choices below that are correct. Increasing the frequency increases the current. Changing the frequency does not affect

the current. Voltage leads current. Current and voltage are in phase. Changing ΔVmax does not affect the current. Changing the resistance does not affect the current. Increasing ΔVmax decreases the current. Increasing the resistance increases the current. Increasing the resistance decreases the current. Increasing ΔVmax increases the current. Current leads voltage. Increasing the frequency decreases the current.
Physics
2 answers:
IgorLugansk [536]3 years ago
6 0

EACH of these statements CAN be true or false.  They ALL depend on the situation, and on the components of the particular circuit.  

For each of these statements, I can give you the diagram of a circuit in which the statement is true, and I can give you the diagram of another circuit in which the same statement is false.

<u>These choices are usually true:</u>

-- Changing the frequency does not affect the current.

-- Increasing the resistance decreases the current.

-- Increasing ΔVmax increases the current.  

<u>These choices are usually false:</u>

-- Increasing the frequency increases the current.

-- Changing ΔVmax does not affect the current.

-- Changing the resistance does not affect the current.  

-- Increasing ΔVmax decreases the current.

-- Increasing the resistance increases the current.

-- Increasing the frequency decreases the current.

<u>These choices can go either way just as easily:</u>

-- Voltage leads current.

-- Current and voltage are in phase.

-- Current leads voltage.

Annette [7]3 years ago
3 0

Answer:

the experyoeyv

Explanation:

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How did Confucius believe that kings should behave? (Site 1) HURRY!!!!!​
ch4aika [34]

Answer:

Confucius believe that kings should behave RIGHTLY

Explanation:

CONFUCIUS  believe that kings are supposed to behave rightly and rule justly ( according to the codes of ethics )  of the land and also live a right and just life.

Confucianism is an ancient philosophy established as far back as the fifth century by Confucius it's main aim was to guide the ancient and modern systems of government in the whole of Asia. it is called a religion by some while some call it a code of ethics and way of leadership

4 1
3 years ago
Problem Page Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 28. g o
sergejj [24]

Answer : The maximum mass of carbon dioxide produced by the chemical reaction can be, 82.3 grams.

Solution : Given,

Mass of C_2H_6 = 28 g

Mass of O_2 = 190 g

Molar mass of O_2 = 32 g/mole

Molar mass of C_2H_6 = 30 g/mole

Molar mass of CO_2 = 44 g/mole

First we have to calculate the moles of C_2H_6 and O_2.

\text{ Moles of }C_2H_6=\frac{\text{ Mass of }C_2H_6}{\text{ Molar mass of }C_2H_6}=\frac{28g}{30g/mole}=0.933moles

\text{ Moles of }O_2=\frac{\text{ Mass of }O_2}{\text{ Molar mass of }O_2}=\frac{190g}{32g/mole}=5.94moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

2C_2H_6+7O_2\rightarrow 4CO_2+6H_2O

From the balanced reaction we conclude that

As, 2 mole of C_2H_6 react with 7 mole of O_2

So, 0.933 moles of C_2H_6 react with \frac{7}{2}\times 0.933=3.26 moles of O_2

From this we conclude that, O_2 is an excess reagent because the given moles are greater than the required moles and C_2H_6 is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of CO_2

From the reaction, we conclude that

As, 2 mole of C_2H_6 react to give 4 mole of CO_2

So, 0.933 moles of C_2H_6 react to give \frac{4}{2}\times 0.933=1.87 moles of CO_2

Now we have to calculate the mass of CO_2

\text{ Mass of }CO_2=\text{ Moles of }CO_2\times \text{ Molar mass of }CO_2

\text{ Mass of }CO_2=(1.87moles)\times (44g/mole)=82.3g

Therefore, the maximum mass of carbon dioxide produced by the chemical reaction can be, 82.3 grams.

6 0
3 years ago
\If we could put all the asteroids together, their total mass would be ________. If we could put all the asteroids together, the
timofeeve [1]

Answer:

much less than the mass of any terrestrial planet

Explanation:

According to www.wikipidia.com

The mass of all the objects of the asteroid belt, lying between the orbits of Mars and Jupiter, is estimated to be about 2.8–3.2×1021 kg, or about 4% of the mass of the Moon. Of this, Ceres comprises 0.95×1021 kg, a third of the total.

While mass of terrestrial planet is

5.97 x 1024 kg (which works out to 5,970,000,000,000 trillion metric tons) Earth is the most massive of all the terrestrial planets (www.universetoday.com)

By doing the calculation, mass of all the asteroid are much less than the mass of any terrestrial planet

8 0
3 years ago
Two particles are fixed on an x axis. Particle 1 of charge 44.9 μC is cated at х- 24.5 cm; particle 2 of charge Q is located at
Kryger [21]

The force that is being exerted on particle 3 by particle 1 is equal to:

F_{13}=\frac{K*Q_1*Q_3}{r13^2}

r_{13} = \sqrt{(0.245m)^2 + (0.245m)^2}=0.3465m^2

F_{13}=\frac{9*10^9Nm^2/C^2*44.9*10^-6C*38.9*10^-6C}{0.3465m^2}=45.37N

As both particles has positive charges, the particles will repel each other and the resultant force will have the direction of the vector r_{13}. Therefore, F_{13} will have x and y components equal to:

F{13x}=F{13}*\frac{r13x}{|r13|}=45.37N*\frac{0.245m}{0.3465m}=32.08 N

F{13y}=F{13}*\frac{r13y}{|r13|}=45.37N*\frac{0.245m}{0.3465m}=32.08 N

In order to calculate Force between particles 2 and 3, we first assume Q2 to be possitive (if it's negative the result will have a negative value, so this doesn't matter). We follow the same line of reasoning we used to calculate F13, just that Q2 will be unknown.

F_{23}=\frac{K*Q_2*Q_3}{r13^2}

r_{23} = \sqrt{(-0.0753m)^2 + (0.245m)^2}=0.2563m^2

F_{23}=\frac{9*10^9Nm^2/C^2*Q_2*38.9*10^-6C}{0.2563m^2}=1.36*10^6Q_2

F{23x}=F{23}*\frac{r23x}{|r23|}=1.36*10^6Q_2*\frac{-0.0753m}{0.2563m}= -401286.15Q_2

F{23y}=F{23}*\frac{r23y}{|r23|}=1.36*10^6Q_2*\frac{0.245m}{0.2563m}=1.305*10^6 Q_2

a) For incise a, F13y + F23y has to be equal to 0:

F{13y}+F{23y}=0

32.08 N+1.305*10^6 Q_2=0

Q_2=\frac{-32.08}{1.305*10^6}=-24.6*10^{-6}C =-24.6uC

b) For incise b, F13x + F23x has to be equal to 0:

F{13x}+F{23x}=0

32.08 N - 401286.15 Q_2=0

Q_2=\frac{32.08}{401286.15}=80*10^{-6}C =80uC

7 0
3 years ago
What are the three formulas (one formula rearranged three ways) which describe the relationship
telo118 [61]

Equation of Newton's second law of motion:

F=ma\\a=\frac{F}{m}\\m=\frac{F}{a}

Explanation:

The equation that gives the relationship between force, mass and acceleration is Newton's second law of motion:

F=ma

where:

F is the net force acting on an object

m is the mass of the object

a is the acceleration of the object

This equation basically tells that whenever there is a net non-zero force acting on an object, the object accelerates.

The equation can be re-arranged in three ways:

(1) F=ma (standard formula)

(2) Then we can re-arrange by making a the subject, and we get

a=\frac{F}{m}

(3) Then we can further re-arrange the make the mass the subject, and we get

m=\frac{F}{a}

Learn more  about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

4 0
3 years ago
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