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Ann [662]
3 years ago
11

Check all choices below that are correct. Increasing the frequency increases the current. Changing the frequency does not affect

the current. Voltage leads current. Current and voltage are in phase. Changing ΔVmax does not affect the current. Changing the resistance does not affect the current. Increasing ΔVmax decreases the current. Increasing the resistance increases the current. Increasing the resistance decreases the current. Increasing ΔVmax increases the current. Current leads voltage. Increasing the frequency decreases the current.
Physics
2 answers:
IgorLugansk [536]3 years ago
6 0

EACH of these statements CAN be true or false.  They ALL depend on the situation, and on the components of the particular circuit.  

For each of these statements, I can give you the diagram of a circuit in which the statement is true, and I can give you the diagram of another circuit in which the same statement is false.

<u>These choices are usually true:</u>

-- Changing the frequency does not affect the current.

-- Increasing the resistance decreases the current.

-- Increasing ΔVmax increases the current.  

<u>These choices are usually false:</u>

-- Increasing the frequency increases the current.

-- Changing ΔVmax does not affect the current.

-- Changing the resistance does not affect the current.  

-- Increasing ΔVmax decreases the current.

-- Increasing the resistance increases the current.

-- Increasing the frequency decreases the current.

<u>These choices can go either way just as easily:</u>

-- Voltage leads current.

-- Current and voltage are in phase.

-- Current leads voltage.

Annette [7]3 years ago
3 0

Answer:

the experyoeyv

Explanation:

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2) Longitudinal wave : here medium particles will move to and fro along the length of the medium and the medium particles will push and pull together along the length of the string.

So here in two types of wave motion it will depends on the medium type as well as it will depend on the source how is wave produced.

So the given type of wave in which particles push together and pull apart the wave must be longitudinal wave.

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The image above was taken by the spacecraft Messenger as it flew by the planet Mercury. The terrain shown in this image is typic
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a skier starts at rest at the top of a hill with 350 J of gravitational potential energy. Assuming energy is conserved, what is
spayn [35]

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350Joules

Explanation:

According to law of Conservation of energy, the amount of energy at the used up at the start is equal to that at the end.

The initial energy used up is gravitational potential energy

Final energy at the lowest point is kinetic energy.

If the energy is conserved then it means energy is not used up during the process hence;

Initial Potential energy = Final kinetic energy

If the gravitational potential energy is 350Joules then her final kinetic energy at the lowest point will also be 350Joules

3 0
3 years ago
A 18.5-cm-diameter loop of wire is initially oriented perpendicular to a 1.9-T magnetic field. The loop is rotated so that its p
Alchen [17]

Answer:

0.3405V

Explanation:

#Given a magnetic field of 1.9T, diameter= 18.5cm(r=9.25cm or 0.0925m), we find the magnetic flux of the loop as:

\phi=B.(\pi r^2)cos 0\textdegree\\=1.9\pi\times 0.0925^2 \times cos 0\textdegree\\=5.107\times10^-^2 \ Tm^2

we can now calculate the induced emf, \frac{\phi}{\bigtriangleup t}:

\frac{\phi}{\bigtriangleup t}=\frac{5.107\times 10^-^2}{0.15}\\=3.405\times 10^-^1V

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8 0
3 years ago
A 190 N child is in a swing that is attached to ropes 2.10 m long. Find the gravitational potential energy of the child-Earth sy
Alekssandra [29.7K]

Answer:

a) Gravitational potential energy = 399 J

b) Gravitational potential energy = 66.5 J

c) Gravitational potential energy = 0 J

Explanation:

Hi there!

Please, see the attached figure for a better understanding of the problem.

a) When the ropes are horizontal, the height of the child, relative to the child's lowest position, is 2.10 m (see figure).

The gravitational potential energy is calculated as follows:

PE = mgh

Where:

PE = potential energy.

mg = weight of the child

h = height.

Then when the ropes are horizontal, the potential energy will be:

PE = 190 N · 2.10 m = 399 J

b) When the ropes make a 34.0° with the vertical, the height of the child is 2.10 m minus x (see figure). To find x, we can use trigonometry of right triangles:

cos angle = adjacent side / hypotenuse

cos 34.0° = x / 2.10 m

x = 2.10 m · cos 34.0° = 1.75 m

Then, the height of the child relative to the lowest position is

(2.10 m - 1.75 m) = 0.35 m

Therefore, the gravitational potential energy will be:

PE = 190 N · 0.35 m

PE = 66.5 J

c) When the child is at the bottom of the circular arc the height is zero (the child is at the lowest position), then, the gravitational potential energy will be zero.

6 0
3 years ago
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