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Ann [662]
3 years ago
11

Check all choices below that are correct. Increasing the frequency increases the current. Changing the frequency does not affect

the current. Voltage leads current. Current and voltage are in phase. Changing ΔVmax does not affect the current. Changing the resistance does not affect the current. Increasing ΔVmax decreases the current. Increasing the resistance increases the current. Increasing the resistance decreases the current. Increasing ΔVmax increases the current. Current leads voltage. Increasing the frequency decreases the current.
Physics
2 answers:
IgorLugansk [536]3 years ago
6 0

EACH of these statements CAN be true or false.  They ALL depend on the situation, and on the components of the particular circuit.  

For each of these statements, I can give you the diagram of a circuit in which the statement is true, and I can give you the diagram of another circuit in which the same statement is false.

<u>These choices are usually true:</u>

-- Changing the frequency does not affect the current.

-- Increasing the resistance decreases the current.

-- Increasing ΔVmax increases the current.  

<u>These choices are usually false:</u>

-- Increasing the frequency increases the current.

-- Changing ΔVmax does not affect the current.

-- Changing the resistance does not affect the current.  

-- Increasing ΔVmax decreases the current.

-- Increasing the resistance increases the current.

-- Increasing the frequency decreases the current.

<u>These choices can go either way just as easily:</u>

-- Voltage leads current.

-- Current and voltage are in phase.

-- Current leads voltage.

Annette [7]3 years ago
3 0

Answer:

the experyoeyv

Explanation:

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<em>-</em><em> </em><em>p</em><em>e</em><em>n</em><em>d</em><em>u</em><em>l</em><em>u</em><em>m</em><em> </em><em>u</em><em>s</em><em>e</em><em> </em><em>t</em><em>o</em><em> </em><em>d</em><em>e</em><em>t</em><em>e</em><em>r</em><em>m</em><em>i</em><em>n</em><em>e</em><em> </em><em>a</em><em>c</em><em>c</em><em>e</em><em>l</em><em>e</em><em>r</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em>

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5 0
3 years ago
How much work output can a 150hp snowmobile do in 15 seconds if it is 18 % efficiency?
Sav [38]

The work output is 3.02\cdot 10^5 J

Explanation:

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Keeping in mind that

1 hp = 746 W

We can convert it into Watts:

P=(150)(746)=111,900 W

The energy used by the snowmobile can be found as follows:

E=Pt

where

P = 111,900 W is the power used

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Substituting,

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However, the snowmobile is 18% efficient: this means that only 18% of this energy is converted into useful work. Therefore, the work output is

W=0.18E=(0.18)(1.68\cdot 10^6)=3.02\cdot 10^5 J

Learn more about power and work:

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3 0
3 years ago
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