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Vesnalui [34]
3 years ago
13

Determine the minimum force P to prevent the 30 kg uniform rod AB from sliding. The contact surface at B is smooth, whereas the

coefficient of static friction between the rod and the wall at A is μs= 0.3.
Engineering
1 answer:
geniusboy [140]3 years ago
4 0

Answer:

88.2N

Explanation:

Coefficient of static friction = force (P)/(mass × acceleration due to gravity)

Force (P) = coefficient of static friction × mass × acceleration due to gravity = 0.3 × 30 × 9.8 = 88.2N

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Determine (with justification) whether the following systems are (i) memoryless, (ii) causal, (iii) invertible, (iv) stable, and
lina2011 [118]

Answer:

a.

y[n] = x[n] x[n-1]  x[n+1]

(i) Memory-less - It is not memory-less because the given system is depend on past or future values.

(ii) Causal - It is non-casual because the present value of output depend on the future value of input.

(iii) Invertible - It is invertible and the inverse of the given system is \frac{1}{x[n] . x[n-1] x[n+1]}

(iv) Stable - It is stable because for all the bounded input, output is bounded.

(v) Time invariant - It is not time invariant because the system is multiplying with a time varying function.

b.

y[n] = cos(x[n])

(i) Memory-less - It is memory-less because the given system is not depend on past or future values.

(ii) Causal - It is casual because the present value of output does not depend on the future value of input.

(iii) Invertible - It is not invertible because two or more than two input values can generate same output values .

For example - for x[n] = 0 , y[n] = cos(0) = 1

                       for x[n] = 2\pi , y[n] = cos(2\pi) = 1

(iv) Stable - It is stable because for all the bounded input, output is bounded.

(v) Time invariant - It is time invariant because the system is not multiplying with a time varying function.

3 0
2 years ago
For the Mohr's circle of a plane-strain element, which of the following changes as a result of shear strain change?
OverLord2011 [107]

Answer:

B

Explanation:

only the radius of the circle as a result of shear strain change.

3 0
3 years ago
true or false incident reports, such as situation reports and status reports enhance situational awareness and ensure that perso
Degger [83]
True becauseidbajqkfkmxzmbakwlgof
4 0
3 years ago
Air enters a turbine with a stagnation pressure of 900 kPa and a stagnation temperature of 658K, and it is expanded to a stagnat
bezimeni [28]

Answer:

12.332 KW

The positive sign indicates work done by the system ( Turbine )

Explanation:

Stagnation pressure( P1 ) = 900 kPa

Stagnation temperature ( T1 ) = 658K

Expanded stagnation pressure ( P2 ) = 100 kPa

Expansion process is  Isentropic, also assume steady state condition

mass flow rate ( m ) = 0.04 kg/s

<u>Calculate the Turbine power </u>

Assuming a steady state condition

( p1 / p2 )^(r-1/r)  = ( T1 / T2 )

= (900 / 100)^(1.4-1/1.4) = ( 658 / T2 )

=  ( 9 )^0.285 = 658 / T2

∴ T2 = 351.22 K

Finally Turbine Power / power developed can be calculated as

Wt = mCp ( T1 - T2 )

    = 0.04 * 1.005 ( 658 - 351.22 )

    = 12.332 KW

The positive sign indicates work done by the system ( Turbine )

6 0
3 years ago
On what frequency can you expect to monitor air traffic in and around<br> Lincoln Airport?
Phantasy [73]

Answer:

118.5

Explanation:

Hope this helps!

5 0
2 years ago
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