Answer:
battery life in year = 9 years and 48 days
Explanation:
given data
Battery Ampere-hours = 1.5
Pulse voltage = 2 V
Pulse width = 1.5 m sec
Pulse time period = 1 sec
Electrode heart resistance = 150 Ω
Current drain on the battery = 1.25 µA
to find out
battery life in years
solution
we get first here duty cycle that is express as
duty cycle = 
...............1
duty cycle = 1.5 × 
and applied voltage will be
applied voltage = duty energy × voltage ...........2
applied voltage = 1.5 × × 2
applied voltage = 3 mV
so current will be
current = 
................3
current = 
current = 20 µA
so net current will be
net current = 20 - 1.25
net current = 18.75 µA
so battery life will be
battery life = 
battery life = 80000 hours
battery life in year = 
battery life in year = 9.13 years
battery life in year = 9 years and 48 days
Answer:
See explanation below.
Explanation:
For this case the program needs to take the inputs as P,r and n and the output would be as A and printed on the system. The code is:
# Inputs
P = float(input("Enter the present value : "))
r = float(input("Enter your APR : "))
n = float(input("Enter the number of years : ") )
# Output
A = P*(1 +(r/100))**n
print("The future values is:", A)
And the result obtained is:
Enter the present value : 1000
Enter your APR : 0.95
Enter the number of years : 5
The future values is: 1048.4111145526908
Answer
Statically determinate beams are those beams in which the unknown reaction forces are equal or less than the equilibrium equation.
As shown in figure 1 in which reaction forces are 3 and we have 3 equilibrium equation so beam is determinate.
Statically indeterminate beams are those beams in which unknown reaction force are more than the equilibrium equation.
As shown in figure 2 in which reaction forces are 6 and we have 3 equilibrium equation so beam is indeterminate.
Answer:
14,700 J
Explanation:
PE = Mgh = (75 kg)(9.8 m/s²)(20 m) = 14,700 J
