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liq [111]
3 years ago
9

In the contemporary approach to control systems, benefits of continuous monitoring include which one of the following? Multiple

Choice dramatically increased time lags
early detection of changes in the competitive environment
reduced organizational flexibility
increased organization response time
Engineering
1 answer:
tangare [24]3 years ago
3 0

Answer:

increased organization response time

Explanation:

The main objective of continuous monitoring is to ensure that customers get access to all the necessary information they need. This also includes the speed and flexibility of the customers' access to vital information. The customers will be able to make valuable decision and the company will benefit immensely.

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3 years ago
Technician A says that proper footwear may include both leather and steel-toed shoes. Technician B says that leather-soled shoes
Amanda [17]

Given:

We have given two statements.

Statement 1: Proper footwear may include both leather and steel-toed shoes.

Statement 2:  Leather-soled shoes provide slip resistance.

Find:

Which statement is true.

Solution:

A slip-resistant outsole is smoother and more slip-resistant than other outsole formulations when exposed to water and oil. A smoother outsole in rubber ensures a slip-resistant shoe can handle a slippery floor more effectively.

Slip resistant shoes have an interlocked tread pattern that does not close the water in, enabling the slip resistant sole to touch the floor to provide better slip resistance.

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5 0
3 years ago
An engineer measures a sample of 1200 shafts out of a certain shipment. He finds the shafts have an average diameter of 2.45 inc
Vadim26 [7]

Answer: 78.89%

Explanation:

Given : Sample size : n=  1200

Sample mean : \overline{x}=2.45

Standard deviation : \sigma=0.07

We assume that it follows Gaussian distribution (Normal distribution).

Let x be a random variable that represents the shaft diameter.

Using formula, z=\dfrac{x-\mu}{\sigma}, the z-value corresponds to 2.39 will be :-

z=\dfrac{2.39-2.45}{0.07}\approx-0.86

z-value corresponds to 2.60 will be :-

z=\dfrac{2.60-2.45}{0.07}\approx2.14

Using the standard normal table for z, we have

P-value = P(-0.86

=P(z

Hence, the percentage of the diameter of the total shipment of shafts will fall between 2.39 inch and 2.60 inch = 78.89%

7 0
3 years ago
The forming section of a plastics plant puts out a continuous sheet of plastic that is 1.2 m wide and 2 mm thick at a rate of 15
KATRIN_1 [288]

Answer:

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Explanation:

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What's the highest grade level that brainly accomodates
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Answer:

The highest grade level is college.

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