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Orlov [11]
4 years ago
5

For the following dimensional equation, find the base dimensions of the parameter f. MM" = a cos(fL) Solution

Chemistry
1 answer:
Cloud [144]4 years ago
6 0

Answer:

L^{-1}.

Explanation:

Given that

MM''= a cos(fL)

We know that all trigonometric function are dimensional less.So fL should be dimension less quantity.

Property                                      Dimension

Length                                            L

Mass                                              M

Force                                            MLT^{-1}

Acceleration                              LT^{-2}

Velocity                                          LT^{-1}    

Torque                                          ML^2T^{-1}

Time                                                    T^{-1}

So in the given question ,dimension of L is L so the dimension of f will become L^{-1}.

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