Answer:
First of all, why are you leaving your house during quarintine. Second of all, its illegal to drink under age.
Explanation:
I'm on the same question. I think the answer is False because you can take step to prevent environment risk factors such as applying sunscreen, avoiding violence and avoiding second-hand smoke. Hope this helps.
Answer: The time period of about 1 msec after an action potential before another one can be initiated -----b
Explanation:Absolute refractory period is the time after an action potential onset when no amount or how strong a stimulus is can cause a second action potential. it is always the time period of 1 m sec between an initiated action potential and an impending next initiated one with the the maximum firing frequency at about 1000 impulses per second.
The absolute refractory period is as a result of molecular processes that triggers the action potential known as sodium channels(tiny pore nerves) . Now the sodium channels exist in three states which are open, close and inactivated states. At rest, the sodium channel is closed, but when a there is an electrical stimulation, the sodium channel opens up to respond to that stimulus which after it passes to the inactivated state, in which the the spores are closed and no matter how strong or the amount an impending next stimulus is, will not cause the pore to open until it has recovered and returned back to the closed state.
Answer:
15.70mg would remain
Explanation:
Partition coefficient is used to extract or purify a solute from a solvent selectively to avoid interference from other substances. For the problem, formula is:
Kp = Concentration 9-fluorenone in ether / Concentration of solute in H₂O
After the solute, 9-fluorenone, is extracted with water, the mass that remains in ether is:
(19mg - X)
<em>Where X is the mass that now is in the aqueous phase</em>
Replacing in Kp formula:
9.5 = (19mg - X) / 5mL / (X /10mL)
0.95X = 19mg - X / 5mL
4.75X = 19 - X
5.75X = 19
X = 19 / 5.75
X = 3.30mg
That means 9-fluorenone that remain in the ether layer is:
19mg - 3.30mg =
<h3>15.70mg would remain</h3>
