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kkurt [141]
3 years ago
9

Solve the following system of equations by using the substitution method.

Mathematics
1 answer:
vampirchik [111]3 years ago
8 0
There appears to be a typing error in the second equation. 

Still the answer is (7,10) because it is the only ordered pair that works for the first equation. 
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HELP!!! CORRECT ANSWER NEEDED OR ELSE I FAIL ;-; STUDY ISLAND !!
Ket [755]

Answer:

  B.  Step 2 uses the associative property, and step 3 uses the commutative property.

Step-by-step explanation:

The associative property lets you group terms for addition any way you like. It appears that in Step 2, the grouping is ...

  4 + (1/6 + 3) + 5/6

The commutative property lets you change the order of any pair of terms involved in addition. It appears that in Step 3, the order of the terms within the group has been swapped.

  4 + (3 + 1/6) + 5/6

_____

<em>Comment on associative and commutative properties</em>

What applies to terms in addition applies to factors in multiplication.

5 0
2 years ago
May I get some help?​
Anarel [89]

Answer:

4 and the correct answer is 34

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
10 points!!! Please help!!!!!!!
babunello [35]
First find slope
5-10/-1-0= 5

find y-intercept
10=5(0)+B
b=-10

equation: y=5x-10
5 0
3 years ago
Read 2 more answers
A bag contains 50 lottery balls, numbered 1-50. A ball is chosen at random, then a month of the year is selected. What is the pr
Morgarella [4.7K]

Answer:

4/75

Step-by-step explanation:

We have two sample spaces

1.Lottery balls

2. Month of the year

For lottery balls the sample space is S= 50

Multiples of 3 between 1 and 50 are

(3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,48)= 16 in numbers

Hence the probability of choosing a multiple of 3

Pr(multiple of 3) = 16/50= 8/25

Also the sample space for months of the year is S= 12

Two months starts with letter m, March and may

Pr(of months with m) = 2/12= 1/6

the probability of choosing a multiple of 3 and a month starting with the letter M= 8/25*1/6= 8/150= 4/75

6 0
3 years ago
If log 2 = a and log 5<br> b then<br> log<br> 32/125
sveta [45]

Answer:

log(32/125)

=log32 - log125 [log(x/y)=log(x) - log(y)]

=log(2)^2 - log(5)^3

=2log2-3log5 [log(x)^p=p log x]

=2a-3b

4 0
3 years ago
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