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3 years ago

13

Which of the following statements accurately describes the atmospheric patterns that influence local weather?

1 answer:

timurjin [86]3 years ago

4 0

Answer: A

Explanation:

Well the high and lows effect the humidity the more humidity the more hot it is so the high brings higher temperatures.

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The sun is 60° above the horizon. Rays from the sun strike the still surface of a pond and cast a shadow of a stick that is stuc

Kipish [7]

Answer:

shadow length 7.67 cm

Explanation:

given data:

refractive index of water is 1.33

by snell's law we have

$n_{air} sin30 =n_{water} sin\theta$

$1*0.5 = 1.33*sin\theta$

solving for $\theta$

$sin\theta = \frac{3}{8}$

$\theta = sin^{-1}\frac{3}{8}$

$\theta = 22 degree$

from shadow- stick traingle

$tan(90-\theta) = cot\theta = \frac{h}{s}$

$s = \frac{h}{cot\theta} = h tan\theta$

s = 19tan22 = 7.67 cm

s = shadow length

5 0

3 years ago

A 3.0 pF capacitor consists of two parallel plates that have surface charge densities of 1.0 nC/mm2 . If the potential between t

Archy [21]

Answer:

$A=81mm^2$

Explanation:

We know that for a capacitor $Q=CV$ , where <em>Q </em>is the charge of one plate, <em>C</em> the capacitance and <em>V</em> the potential between the plates.

We also know that $Q=\sigma A$ , since $\sigma$ is the surface charge density and <em>A</em> the area of the plate (both equal in our case).

Putting all together:

$A=\frac{CV}{\sigma}$

Which for our values is:

$A=\frac{(3\times10^{-12}F)(27\times10^3V)}{1\times10^{-9}C/mm^2}=81mm^2$

Where we notice that the S.I. units combination FV/C must not have units (we can verify it directly from their definitions or we notice that $mm^2$ is enough to describe an area).

8 0

3 years ago

A solar panel is used to collect energy from the sun and change it into other forms of energy. The picture below shows some sola

irakobra [83]

C I’m pretty sure!!!!!

4 0

3 years ago

A gas is compressed at constant temperature from a volume of 5.68 L to a volume of 2.35 L by an external pressure of 732 torr. C

Vlada [557]

Answer: The work done in J is 324

Explanation:

To calculate the amount of work done for an isothermal process is given by the equation:

$W=-P\Delta V=-P(V_2-V_1)$

W = amount of work done = ?

P = pressure = 732 torr = 0.96 atm (760torr =1atm)

$V_1$ = initial volume = 5.68 L

$V_2$ = final volume = 2.35 L

Putting values in above equation, we get:

$W=-0.96atm\times (2.35-5.68)L=3.20L.atm$

To convert this into joules, we use the conversion factor:

$1L.atm=101.33J$

So, $3.20L.atm=3.20\times 101.3=324J$

The positive sign indicates the work is done on the system

Hence, the work done for the given process is 324 J

5 0

3 years ago

All but one statement applies to electromagnetic radiation

lina2011 [118]

<span>D) Electromagnetic radiation travels in the form of longitudinal waves.</span>

3 0

3 years ago