Answer:
the cat is 0.4238 m in front of the dog as it leaps through the window
Explanation:
Given that;
acceleration a = 0.85 m/s²
speed v = 1.40 m/s
the cat is at rest, so initial velocity u = 0
we know that, since the cat is sleeping on the floor in the middle of a 2.8-m-wide room, it needs to cover (2.8 m / 2 ) distance to get to the window;
using the second equation equation of motion;
s = ut + 1/2 at²
we substitute
2.8/2 = 0×t + 1/2 × 0.85 × t²
1.4 = 0.425t²
t = √( 1.4 / 0.425 )
t = 1.81497 sec
now, at acceleration 0.10 m/s²
the dog has to cover the distance;
s = ut + 1/2 at²
s = ( 1.4 × 1.81497) - 1/2 × 0.10 × 1.81497²
s = 2.540958 - 0.1647
s = 2.3762 m
The cant in front of the dog as it leaps through the window;
distance = 2.8 m - 2.3762 m
distance = 0.4238 m
Therefore, the cat is 0.4238 m in front of the dog as it leaps through the window
Answer:
Hans is more powerful
Explanation:
Power: This can be defined as the rate at which work is done or energy is used up.
The expression for power is given as,
P = E/t
P = mgh/t................. Equation 1
Where P = power, W = Work, t = time, m = mass, h = height, g = acceleration due to gravity.
Hans' power
P = mgh/t
Given: m = 100 kg, h = 2 m, g = 9.8 m/s², t = 3 s
Substitute into equation 1
P = 100(9.8)(2)/3
P = 653.33 W.
Frans' power
P' = mgh/t
Given; m = 200 kg, h = 5 m, t = 20 s.
P' = 200(5)(9.8)/20
P' = 9800/20
P' = 490 W
from the above,
since P>P'
Hence, Hans is more powerful
Answer:
Because the velocity v (As a Vector ) is going opposite direction ( -X axis ) .
Playing catch involves the ball moving in one direction in the air when you exert force. When the ball is in air, there is a gravitational force and a little it of backward air resistance until the other person catches it.
