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qwelly [4]
3 years ago
6

Which of the following groups contains mostly radioactive elements?

Chemistry
2 answers:
Blizzard [7]3 years ago
6 0

Answer:

Inner transition metals

Explanation:

The inner transition metals are also known as rare earth metals. The rare earth metals includes Lanthanide and Actinide Series of the periodic table. The elements with atomic numbers 89 to 103 are placed in the third group of the periodic table are Actinides. Examples are uranium and plutonium. These elements are with high oxidation number are radioactive elements. Thus, the inner transition metals are radioactive elements.

lukranit [14]3 years ago
6 0

Answer:

inner transition metals

Explanation:

The inner transition metals consists mostly of the f-block elements. They comprise of lanthanides and actinides. Many of them are radioactive because they possess atomic numbers greater than 82, hence their nuclei are unstable. Many of them are synthetic elements hence they are highly radioactive with very short half lives.

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I think the most appropriate answer is: the solvent being used in the experiment
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The height of a wave is called its amplitude. From the noises of the mosquito and the air boat, which aspect of sound is related
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3 years ago
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Answer:

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What mass of FeSO4^2- x 6H20 (Molar Mass=260g/mol) is required to produce 500 mL of a .10M iron (II) sulfate solution.
lukranit [14]

Answer:

The correct option is: B. 13g

Explanation:

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Molarity of iron (II) sulfate solution: M =  0.1 M,

Volume of iron (II) sulfate solution: V = 500 mL = 500 × 10⁻³ = 0.5 L           (∵ 1L = 1000mL)

Mass of iron (II) sulfate taken: w = ? g

<em>Molarity</em>: M = \frac{n}{V (L)} = \frac{w}{m\times V(L)}

Here, n- total number of moles of solute, w - given mass of solute, m- molar mass of solute, V- total volume of solution in L

∴ <em>Molarity of iron (II) sulfate solution:</em>  M = \frac{w}{m\times V(L)}

⇒  w = M\times m\times V(L)

⇒  w = (0.1 M)\times (260g/mol)\times (0.5L)

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<u>Therefore, the mass of iron (II) sulfate taken for preparing the given solution is 13 g.</u>

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