The reaction will generally form more reactants than products.
        
                    
             
        
        
        
Answer:
The correct answer is vertebrate enzyme hydrolyze alpha-1,4 glycosidic linkage but not glucose in the beta configuration.
Explanation:
The amylase that is present inside human body is called salivary alpha amylase,an enzyme that digest the alpha-1,4-glycosidic linkages of starch but does not act on those glycosidic linkages which are present in beta configuration.
        Cellulose contain beta-1,4-glycosidic linkages.That"s why it is not digested by the alpha amylase enzyme present inside the human body basically present in the saliva.
 
        
                    
             
        
        
        
First, we calculate the mass of the sample:
mass = density x volume
mass = 8.48 x 112.5
mass = 954 grams
Now, we will calculate the mass of each component using its percentage mass, then divide it by its atomic mass to find the moles and finally multiply the number of moles by the number of particles in a mole, that is, 6.02 x 10²³.
Zinc mass = 0.37 x 954
Zinc mass = 352.98 g
Zinc moles = 352.98 / 65
Zinc moles = 5.43
Zinc atoms = 5.43 x 6.02 x 10²³
Zinc atoms = 3.27 x 10²⁴
Copper mass = 0.63 x 954
Copper mass = 601.02 g
Copper moles = 601.02 / 64
Copper moles = 9.39
Copper atoms = 9.39 x 6.02 x 10²³
Copper atoms = 5.56 x 10²⁴
        
             
        
        
        
Answer:
1.69.
Explanation:
- The solution = 12.0 / 7.11 = 1.687 = 1.69.
- The rule of significant figures for division states that: the results are reported to the fewest significant  figures.
- 12.0 contains 3 significant figures.
- 7.11 contains 3 significant figures.
So, the solution should contain 3 significant figures.
- Now, the issue id of rounding; In a series of calculations, carry the extra digits through to  the final result, then round.
- If the digit to be removed is equal to or greater than 5, the preceding digit is  increased by 1. 
- The digit that should be removed is 7 that is larger than 5 so increase the preceding digit by 1.