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3 years ago

An object has a velocity of 8 m/s and a kinetic energy of 480 J. What is the mass of the object? (Formula: )

2 answers:

7 0

KE = 1/2 * m * v2

We have to rearrange this so the subject is mass. (because the question asks for the mass of the object) :

Mass = (2 * KE) / v

Now input the values into this equation to get your answer :

Mass = (2 * KE) / v
Mass = (2 * 480) / 8
Mass = 960 / 8
Mass = 120

bulgar [2K]3 years ago

7 0

Answer:

Mass of an object is 15 kg.

Explanation:

It is given that,

velocity of an object, v = 8 m/s

Kinetic energy of an object, KE = 480 J

Kinetic energy of an object is due to the motion of an object. The mathematical relationship is given by :

$KE=\dfrac{1}{2}mv^2$

Where m is the mass of an object

$m=\dfrac{2\times KE}{v^2}$

$m=\dfrac{2\times 480\ J}{(8\ m/s)^2}$

m = 15 kg

Hence, the mass of an object is 15 kg

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3 years ago

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Which statement is true about an object moving in a circular motion due to centripetal force, F, when the mass is doubled? A. It

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Force = [Mass x (velocity)^2]/Radius
Therefore,
The mass and the force are directly proportional.If you double the mass,the force will be doubled too.

A. Its centripetal force would be doubled.

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3 years ago

If you are over-driving your headlights and you see an object ahead, you will_____. be given the right-of-way from other vehicle

SashulF [63]

Answer: not be able to stop in time to miss the object

Explanation:

The phrase "Over-driving your headlights" means that a person is driving at such a speed that the vehicle's stopping distance is greater than the maximum viewable distance with the headlights on.

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5 0

3 years ago

(1) Develop an equation that relates the rms voltage of a sine wave to its peak-to-peak voltage. a. If a sine wave has a peak-to

Aleks04 [339]

Answer:

(A) Equation will be $v=v_msin\omega t=0.75sin(18840t)$

(B) RMS value of voltage will be 0.530 volt

Explanation:

We have given peak to peak voltage of ac wave = 1.5 volt

Peak to peak voltage of ac wave is equal to 2 times of peak voltage

So $2v_{peak}=1.5volt$

$v_{peak}=\frac{1.5}{2}=0.75volt$

Frequency of ac wave is given f = 3 kHz

So angular frequency $\omega =2\pi f$ = 2×3.14×3000 = 18840 rad/sec

So expression of equation will be $v=v_msin\omega t=0.75sin(18840t)$ ( As phase difference is 0 )

Now we have to find the rms value of voltage

So rms voltage will be equal to $v_{rms}=\frac{v_{peak}}{\sqrt{2}}=\frac{0.75}{1.414}=0.530volt$

4 0

3 years ago

Question number 11 how did we found the answer ?

BaLLatris [955]

Answer:

Option A. 57.14 Ω

Explanation:

From the question given above, the following data were obtained:

Resistor 1 (R₁) = 100 Ω

Resistor 2 (R₂) = 400 Ω

Resistor 3 (R₃) = 200 Ω

Equivalent Resistor (Rₚ) =?

The equivalent resistor in the above circuit can be obtained as follow:

1/Rₚ = 1/R₁ + 1/R₂ + 1/R₃

1/Rₚ = 1/100 + 1/400 + 1/200

Find the least common multiple (lcm) of 100, 400 and 200. The result is 400. Divide 400 by 100, 200 and 400 respectively and multiply the result with the numerator as shown

1/Rₚ = (4 + 1 + 2)/400

1/Rₚ = 7/400

Invert

Rₚ = 400/7

Rₚ = 57.14 Ω

6 0

3 years ago