Answer:
1.04g
Explanation:
Step 1:
The balanced equation for the reaction.
2Fe(NO3)3(aq) + 3Na2CO3(aq) → Fe2(CO3)3(s) + 6NaNO3(aq)
Step 2:
Determination of mass of Fe(NO3)3 that reacted and the mass of Fe2(CO3)3 that is produced from the balanced equation.
This is shown below:
Molar Mass of Fe(NO3)3 = 241.88g/mol
Mass of Fe(NO3)3 from the balanced equation = 2 x 241.88 = 483.76g
Molar Mass of Fe2(CO3)3 = 291.73g/mol
Summary:
From the balanced equation above,
483.76g of Fe(NO3)3 reacted to produce 291.73g of Fe2(CO3)3.
Step 3:
Determination of the theoretical yield of Fe2(CO3)3. This is illustrated below:
From the balanced equation above,
483.76g of Fe(NO3)3 reacted to produce 291.73g of Fe2(CO3)3.
Therefore, 1.72g of Fe(NO3)3 will react to produce = (1.72x291.73)/483.76 = 1.04g of Fe2(CO3)3
Therefore, the theoretical yield of Fe2(CO3)3 is 1.04g