Answer:
68.7% is the percent of frozen freshwater.
<span>Copper II Sulfate- Cu 2+ and a sulfate SO4 2- add together nicely to make CuSO4. </span>
Answer : The limiting reactant is 
Explanation : Given,
Mass of 
= 30.0 g
Mass of = 75.0 g
Molar mass of = 44 g/mole
Molar mass of = 32 g/mole
First we have to calculate the moles of and .
Now we have to calculate the limiting and excess reagent.
The balanced chemical reaction is,
From the balanced reaction we conclude that
As, 5 mole of react with 1 mole of
So, 2.34 moles of react with 
moles of
From this we conclude that, is an excess reagent because the given moles are greater than the required moles and is a limiting reagent and it limits the formation of product.
Therefore, the limiting reactant is
One can solve the problem by using the law of conservation of momentum. The total momentum prior to the collision must be equivalent to the total momentum after the collision, so we have:
m1v1 + m2v2 = m1v1 + m2v2
Here, m1 is 0.4 Kg that is the mass of the ball, u1 is 18 m/s that is the initial velocity of the ball, m2 is 0.2 Kg that is the mass of the bottle, and u2 is 0 that is the initial velocity of the bottle.
v1 is the final velocity of the ball, which is to be determined, and v2 is 25 m/s that is the final velocity of the bottle.
Substituting and rearranging the equation, one can find the final velocity of the ball:
v1 = m1u1 - m2v2 / m1 = (0.4 kg) (18 m/s) - (0.2 Kg) (25 m/s) / 0.4 Kg = 5.5 m/s.
