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stiv31 [10]
3 years ago
12

What is one property for each of the chemical substances listed above?

Chemistry
1 answer:
Vilka [71]3 years ago
8 0
1. Acetic acid (Ethanoic acid) is a colorless liquid.

2. Sodium Bicarbonate is an odorless, crystalline powder.

3. Carbon dioxide is a colorless gas.

4. Dihydrogen monoxide is colorless and odorless gas.

5. Sodium acetate is very soluble in water.

6. Calcium chloride has an exothermic reaction when dissolved in water.

7. Calcium carbonate is also an odorless powder.

8. Sodium chloride is soluble in water, and partially soluble (or insoluble) in other liquids.

Hope this helps! (:
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These substances are all ____. H2O2 Li NaCl O2
Bogdan [553]

Answer: pure substances.


Explanation:


The given substances are:

  • H₂O₂
  • Li
  • NaCl
  • O₂

All what surrounds us, which has mass and occupies spaces, is matter. There are two kind of matter: pure substances and mixtures.


Pure substances have a uniform and constant composition. On the other hand, mixtures are combinations of two or more pure substances in  any arbitratry ratio.


Pure substances may be elements or compounds. The elements are the substances conmposed by one only kind of atom. In the list of substances given, Li and O₂ are elements: all the atoms in Li are lithium, and all the atoms in O₂ are oxygen atoms.


Compounds are the chemical combination of two or more different kind of atoms. In the given list H₂O₂ and NaCl are compounds. As you see, H₂O₂ contains atoms of hydrogen and oxygen, chemically bonded, in a fixed ratio (2 atoms of hydrogen by 2 atoms of oxygen). And NaCl has atoms of Na (sodium) and Cl (chlorine), chemicaly bonded, in a fixed ratio (1:1).


There are only 118 known elements and you can find them in any modern periodic table. Therer are virtually infinitely many compounds since many different combinations of the elements can be attained.


Elements and compounds have in common that they are classified as pure substances.


7 0
3 years ago
What is the mass of 1.58 moles of CH4
HACTEHA [7]
<h3>Answer:</h3>

25.4 g CH₄

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

1.58 mol CH₄

<u>Step 2: Identify Conversions</u>

[PT] Molar Mass of C - 12.01 g/mol

[PT] Molar Mass of H - 1.01 g/mol

Molar Mass of CH₄ - 12.01 + 4(1.01) = 16.05 g/mol

<u>Step 3: Convert</u>

  1. Set up:                               \displaystyle 1.58 \ mol \ CH_4(\frac{16.05 \ g \ CH_4}{1 \ mol \ CH_4})
  2. Multiply/Divide:                 \displaystyle 25.359 \ g \ CH_4

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

25.359 g CH₄ ≈ 25.4 g CH₄

4 0
3 years ago
a 10.99g sample of NaBr contains 22.34% Na by mass. Considering the law of constant composition (define proportions), how many g
leonid [27]

Given :

A 10.99 g sample of NaBr contains 22.34% Na by mass.

To Find :

How many grams of sodium does a 9.77g sample of sodium bromine contain.

Solution :

By law of constant composition , in any given chemical compound, the elements always combine in the same proportion with each other.

Therefore , percentage of Na by mass in NaBr will be same for every amount .

Percentage of Na in 9.77 g NaBr is 22.34 % too .

Gram of Na = 9.77\times \dfrac{22.34}{100}=2.18\ g .

Hence , this is the required solution .

7 0
3 years ago
Under which conditions of temperature and pressure does a real gas behave most like an ideal gas
Veseljchak [2.6K]
At higher temperature, and lower pressure. 
4 0
3 years ago
What is steel and why is it better than iron?
7nadin3 [17]
Steel is practically one of the worlds most important metals to use in construction, it is harder and stronger than iron can be. You can say iron is the base metal of steel, if you need more info, just ask :>
5 0
3 years ago
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