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stiv31 [10]
2 years ago
12

What is one property for each of the chemical substances listed above?

Chemistry
1 answer:
Vilka [71]2 years ago
8 0
1. Acetic acid (Ethanoic acid) is a colorless liquid.

2. Sodium Bicarbonate is an odorless, crystalline powder.

3. Carbon dioxide is a colorless gas.

4. Dihydrogen monoxide is colorless and odorless gas.

5. Sodium acetate is very soluble in water.

6. Calcium chloride has an exothermic reaction when dissolved in water.

7. Calcium carbonate is also an odorless powder.

8. Sodium chloride is soluble in water, and partially soluble (or insoluble) in other liquids.

Hope this helps! (:
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3 years ago
How do you convert volume to moles at STP?
Vanyuwa [196]

The conversion of volume to moles at STP is 1 mole.

The ideal gas equation is given as :

P V = n R T

where,

P = pressure of the gas

V = volume of the gas

n = ?

R = constant = 0.823 atm L / mol K

T = temperature

At STP , the pressure is 1 atm and the temperature is 273.15 K, the volume At STP is 22.4 L.

moles , n = P V / R T

n = ( 1 × 22.4 ) / (0.0823 × 273.15)

n = 1 mole

Thus, at STP , the number of moles is 1 mol.

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6 0
1 year ago
What is the difference between a mixture and compound
bonufazy [111]
A compound is made up of a single type of molecule. A mixture, on the other hand, is made up of different substances that can be distinguished from one another.
As an example:
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3 0
3 years ago
How many milliliters of a 0.285 M HCl solution are needed to neutralize 249 mL of a 0.0443 M Ba(OH)2 solution?
meriva

Answer:

\large \boxed{\text{77.4 mL}}

Explanation:

                Ba(OH)₂ + 2HCl ⟶ BaCl₂ + H₂O

    V/mL:     249

c/mol·L⁻¹:  0.0443     0.285

1. Calculate the moles of Ba(OH)₂

\text{Moles of Ba(OH)$_{2}$} = \text{0.249 L Ba(OH)}_{2} \times \dfrac{\text{0.0443 mol Ba(OH)}_{2}}{\text{1 L Ba(OH)$_{2}$}} = \text{0.011 03 mol Ba(OH)}_{2}

2. Calculate the moles of HCl

The molar ratio is 2 mol HCl:1 mol Ba(OH)₂

\text{Moles of HCl} = \text{0.011 03 mol Ba(OH)}_{2} \times \dfrac{\text{2 mol HCl}}{\text{1  mol Ba(OH)}_{2}} = \text{0.022 06 mol HCl}

3. Calculate the volume of HCl

V_{\text{HCl}} = \text{0.022 06 mol HCl} \times \dfrac{\text{1 L HCl}}{\text{0.285 mol HCl}} = \text{0.0774 L HCl} = \textbf{77.4 mL HCl}\\\\\text{You must add $\large \boxed{\textbf{77.4 mL}}$ of HCl.}

8 0
3 years ago
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