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4 years ago

Does current flow through or across a resistor?

Physics

2 answers:

Tanzania [10]4 years ago

6 0

It's not exactly clear what you think the difference is between "through" and "across".

A resistor has two wires. Electric current that flows into one wire, continues through the entire body of the resistor and out through the other wire. If there's a crack or break anywhere along the body of the resistor, the circuit will be 'open' and the current will stop flowing.

Now, if you were to connect a voltmeter between the ends of the resistor, the meter would measure and indicate the difference in electric potential between those two points. That would be called the voltage 'across' the resistor. Numerically, it would be equal to the product of the resistor's resistance and the current through it.

Mamont248 [21]4 years ago

3 0

Answer:

Current flows across a resistor.

Explanation:

Please mark brainliest and have a great day!

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A kid pulls on a rope with 20 newtons of force. The block and tackle system pulls up a 160 newton box. What is the mechanical ad

Minchanka [31]

Answer:
The mechanical advantage of the system is 8

Explanation:
the mechanical advantage measures how much the system multiplies the input force to get the output.

In the given:
The input force (effort) is 20 Newton
The output force (load) is 160 Newton

This means that the mechanical advantage is:
mechanical advantage = load / effort = 160 / 20 = 8

Note that the mechanical advantage is unit-less (has no unit) since it is a ratio between two forces.

Hope this helps :)

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3 years ago

If Frequency F, velocity v, and density D are considered fundamental units, the dimensional formula for momentum will be :

gizmo_the_mogwai [7]

Let's see

Momentum be P

$\\ \rm\Rrightarrow P=[Frequency]^a[velocity]^b[Density]^c$

$\\ \rm\Rrightarrow [P]=[F]^a[v]^b[D]^c$

$\\ \rm\Rrightarrow [M^1L^1T^{-1}]=[T^{-1}]^a[L^1T^{-1}]^b[M^1L^{-3}]^c$

$\\ \rm\Rrightarrow MLT^{-1}=T^{-a}L^bT^{-b}M^cL^{-3c}$

$\\ \rm\Rrightarrow MLT^{-1}=T^{-a-b}L^{b-3c}M^c$

On comaparing

b-3c=1
b-3=1
b=1+3
b=4

and

-a-b=-1
-a-4=-1
-a=-1+4=3
a=-3

So the unit is

DV⁴/F³

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kramer

In solids: All metals are good conductors of electricity as they contain free moving electrons. Non-metals doesn't conduct , but we consider Graphite the only non-metal that can conduct electricity for the presence of free moving electrons.

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