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Andreyy89
4 years ago
9

Does current flow through or across a resistor?

Physics
2 answers:
Tanzania [10]4 years ago
6 0

It's not exactly clear what you think the difference is between "through" and "across".

A resistor has two wires.  Electric current that flows into one wire, continues <em>through</em> the entire body of the resistor and out <em>through</em> the other wire.  If there's a crack or break anywhere along the body of the resistor, the circuit will be 'open' and the current will stop flowing.

Now, if you were to connect a <em>voltmeter</em> between the ends of the resistor, the meter would measure and indicate the difference in electric potential between those two points.  That would be called the voltage '<u><em>across</em></u>' the resistor.  Numerically, it would be equal to the product of the resistor's resistance and the current through it.  

Mamont248 [21]4 years ago
3 0

Answer:

Current flows across a resistor.

Explanation:

Please mark brainliest and have a great day!

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While on the moon, the Apollo astronauts enjoyed the effects of a gravity much smaller than that on
Ainat [17]

Answer:

1.628 \frac{m}{sec^{2} }

Explanation:

Anywhere in the universe, In a closed system, <u>Conservation of energy</u> is applicable.

In this case

Neil is initially on the surface of moon and has a velocity of 1.51 \frac{m}{sec} in upward direction.

⇒He has Kinetic energy= K_{i} = \frac{1}{2} m{v^{2} } J

But with respect to the surface of the moon,

where m=mass of moon

           v=velocity of Neil

He has Potential energy= P_{i}=0 J

At the highest point of his jump, his velocity =0

⇒ Kinetic energy=K_{f}=0 J

His Potential energy with respect to the surface of moon=P_{f}=m \times g\times h

where m=mass of moon

           g= gravitational acceleration on moon

           h=height from moon's surface

By Conservation Energy Principle

K_{i}+P_{i}=K_{f}+P_{f}

K_{i}+0=0+P_{f}

\frac{1}{2} m{v^{2} } = m \times g\times h

\frac{v^{2} }{2} =  g\times h

\frac{1.5^{2} }{2} J= g\times 0.7 m

⇒ g = \frac{1.14}{0.7} = 1.628 \frac{m}{sec^{2} }

8 0
3 years ago
A blinking light of constant period is situated on a lab cart. Which diagram best represents a photograph of light, taken every
Karo-lina-s [1.5K]

The snapshot of light as the cart moves with constant velocity is represented by a graph with uniform displacement at each time interval.

The change in displacement with time is uniform at constant velocity. The displacement of the supplied moving item grows at the same pace.

The beginning velocity equals the ultimate velocity at constant velocity.

v₁ = v₂

The object's acceleration at constant velocity is zero since the velocity change with time is zero.

As a result, we may deduce that the graph with equal displacement at each time interval reflects a snapshot of light as the cart moves at a constant speed.

A moving object's displacement-time graph shows the distance traveled by a moving item as time passes. A vector quantity is displacement. The slope or gradient of this graph represents the velocity of the item. The displacement-time graph, also known as the position-time graph, describes an object's motion. In this graph, the displacement of the moving item is displayed on the y-axis as a dependent variable, while time is shown on the x-axis as an independent variable.

Learn more about Uniform displacement here:

brainly.com/question/22102874

#SPJ1

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ElenaW [278]
The answer is B. Transfer electrons
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