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Andreyy89
3 years ago
9

Does current flow through or across a resistor?

Physics
2 answers:
Tanzania [10]3 years ago
6 0

It's not exactly clear what you think the difference is between "through" and "across".

A resistor has two wires.  Electric current that flows into one wire, continues <em>through</em> the entire body of the resistor and out <em>through</em> the other wire.  If there's a crack or break anywhere along the body of the resistor, the circuit will be 'open' and the current will stop flowing.

Now, if you were to connect a <em>voltmeter</em> between the ends of the resistor, the meter would measure and indicate the difference in electric potential between those two points.  That would be called the voltage '<u><em>across</em></u>' the resistor.  Numerically, it would be equal to the product of the resistor's resistance and the current through it.  

Mamont248 [21]3 years ago
3 0

Answer:

Current flows across a resistor.

Explanation:

Please mark brainliest and have a great day!

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3 years ago
A mass of 250 N is on a piston of 2.0 m^2. What force is needed to lift this piston if the area of the second piston is 0.5 m^2?
prohojiy [21]

Answer:

<h3>62.5N</h3>

Explanation:

The pressure at one end of the piston is equal to the pressure on the second piston.

Pressure = Force/Area

F1/A1 = F2/A2

Given

F1 = 250N

A1 = 2.0m²

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F2 = ?

Substituting the given values in the formula;

250/2 = F2/0.5

cross multiply

250*0.5 = 2F2

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F2 = 125/2

F2 = 62.5N

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8 0
3 years ago
We want to find how much charge is on the electrons in a nickel coin. Follow this method. A nickel coin has a mass of about 4.2
monitta

Answer:

The number of atoms is N = 4.37*10^{22} \ atoms

Explanation:

From the question we are told that

                 The mass of coin  is m_n = 4.2g

                   Number of atom in one mole = n =6.02*10^{23} \ atoms

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Now the relation to obtain the number of atom in  the  nickel coin is

                        N = \frac{Mass \ of Nickel\ coin}{Molar \ mass\ of nickel }  * No\ of\atoms \ in \ \ one\  mole\ of\ nickel

                           = \frac{4.2}{57.8}* 6.02*10^{23}

                           =4.37 *10^{22} atoms

                 

     

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