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Andreyy89
4 years ago
9

Does current flow through or across a resistor?

Physics
2 answers:
Tanzania [10]4 years ago
6 0

It's not exactly clear what you think the difference is between "through" and "across".

A resistor has two wires.  Electric current that flows into one wire, continues <em>through</em> the entire body of the resistor and out <em>through</em> the other wire.  If there's a crack or break anywhere along the body of the resistor, the circuit will be 'open' and the current will stop flowing.

Now, if you were to connect a <em>voltmeter</em> between the ends of the resistor, the meter would measure and indicate the difference in electric potential between those two points.  That would be called the voltage '<u><em>across</em></u>' the resistor.  Numerically, it would be equal to the product of the resistor's resistance and the current through it.  

Mamont248 [21]4 years ago
3 0

Answer:

Current flows across a resistor.

Explanation:

Please mark brainliest and have a great day!

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3 years ago
What is 1.2 kg converted into mg.<br> I need to know for step by step please?
astra-53 [7]
Here’s a good photo to reference when converting in the metric system.

Each time you move down a step you move the decimal to the right, each time you move up a step you move the decimal to the left.

We are going from 1.2 kg or kilograms, which is at the very top left of the ladder. To get to mg or milligrams, we would have to make six jumps, so we’d move the decimal over six times.

1.2 > 12. > 120. > 1200. > 12000. > 120000. > 1200000.

So our final answer would be 1,200,000mg.
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How do we find the average force in physics?​
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8 0
3 years ago
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In what ways are directions slightly distorted on the gore map
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4 0
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A vacuum gage connected to a chamber reads 39 kPa at a location where the atmospheric pressure is 92 kPa. Determine the absolute
Nata [24]

Answer: 53 kPa

Explanation:

Absolute pressure is a pressure value referred to absolute zero or vacuum. This value indicates the total pressure to which a body or system (the chamber in this situation) is subjected, considering the total pressure acting on it.

In this sense, the equation that will be useful in this case is:

P_{atmospheric}= P_{absolute} + P_{vacuum}  (1)

Where:

P_{atmospheric}=92 kPa is the atmospheric pressure

P_{vacuum}=39 kPa is the vacuum pressure

P_{absolute} is the absolute pressure

Isolating P_{absolute}  from (1):

P_{absolute}=P_{atmospheric} - P_{vacuum}  (2)

P_{absolute}=92 kPa - 39 kPa  (3)

Finally:

P_{absolute}=53 kPa=53(10)^{3} Pa This is the absolute pressure in the chamber

7 0
4 years ago
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