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3 years ago

Does current flow through or across a resistor?

Physics

2 answers:

Tanzania [10]3 years ago

6 0

It's not exactly clear what you think the difference is between "through" and "across".

A resistor has two wires. Electric current that flows into one wire, continues through the entire body of the resistor and out through the other wire. If there's a crack or break anywhere along the body of the resistor, the circuit will be 'open' and the current will stop flowing.

Now, if you were to connect a voltmeter between the ends of the resistor, the meter would measure and indicate the difference in electric potential between those two points. That would be called the voltage 'across' the resistor. Numerically, it would be equal to the product of the resistor's resistance and the current through it.

Mamont248 [21]3 years ago

3 0

Answer:

Current flows across a resistor.

Explanation:

Please mark brainliest and have a great day!

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A generator uses a coil that has 100 turns and a 0.50-T magnetic field. The frequency of this generator is 60.0 Hz, and its emf

lana [24]

Answer:

38 m

Explanation:

Number of turns=N=100

Magnetic field=B=0.50 T

Frequency of the generator=f=60 Hz

Rms value of emf= $E_{rms}=120 V$

We have to find the length of the wire from which the coil is made.

Peak value of emf= $E_0=E_{rms}\sqrt 2=120\times \sqrt 2=169.7 V$

Length of wire= $4\sqrt{\frac{NE_0}{2\pi fB}}$

Substitute the values

Length of wire= $4\times \sqrt{\frac{169.7\times 100}{0.50\times 2\pi\times 60}}$

Length of wire=38 m

Hence, the length of wire from which the coil is made=38 m

6 0

2 years ago

Which of the following is not a part of the appendicular skeleton

Bingel [31]

Answer:

Hyoid

Explanation:

The hyoid is located in the neck area, not the limbs.

7 0

3 years ago

A pirate fires his cannon parallel to the water but 3.5 m above the water. The cannonball leaves the cannon with a velocity of 1

Bumek [7]

Answer:

202.8m

Explanation:

Given that A pirate fires his cannon parallel to the water but 3.5 m above the water. The cannonball leaves the cannon with a velocity of 120 m/s. He misses his target and the cannonball splashes into the briny deep.

First calculate the total time travelled by using the second equation of motion

h = Ut + 1/2gt^2

Let assume that u = 0

And h = 3.5

Substitute all the parameters into the formula

3.5 = 1/2 × 9.8 × t^2

3.5 = 4.9t^2

t^2 = 3.5/4.9

t^2 = 0.7

t = 0.845s

To know how far the cannonball travel, let's use the equation

S = UT + 1/2at^2

But acceleration a = 0

T = 2t

T = 1.69s

S = 120 × 1.69

S = 202.834 m

Therefore, the distance travelled by the cannon ball is approximately 202.8m.

4 0

2 years ago

Calculate the orbital period of a dwarf planet found to have a semimajor axis of a = 4.0x 10^12 meters in seconds and years.

padilas [110]

Explanation:

We have,

Semimajor axis is $4\times 10^{12}\ m$

It is required to find the orbital period of a dwarf planet. Let T is time period. The relation between the time period and the semi major axis is given by Kepler's third law. Its mathematical form is given by :

$T^2=\dfrac{4\pi ^2}{GM}a^3$

G is universal gravitational constant

M is solar mass

Plugging all the values,

$T^2=\dfrac{4\pi ^2}{6.67\times 10^{-11}\times 1.98\times 10^{30}}\times (4\times 10^{12})^3\\\\T=\sqrt{\dfrac{4\pi^{2}}{6.67\times10^{-11}\times1.98\times10^{30}}\times(4\times10^{12})^{3}}\\\\T=4.37\times 10^9\ s$

Since,

$1\ s=3.17\times 10^{-8}\ \text{years}\\\\4.37\times 10^9\ s=4.37\cdot10^{9}\cdot3.17\cdot10^{-8}\\\\4.37\times 10^9\ s=138.52\ \text{years}$

So, the orbital period of a dwarf planet is 138.52 years.

3 0

2 years ago

What happens when the falling object reaches its terminal velocity? It will stop _________

lora16 [44]

Answer:

LOL i don't even know

Explanation:

7 0

2 years ago