What force is required to accelerate a body with a mass of 15 kilograms at a rate of 8 m/s²?

The unit light-year is a measure of

Virty [35]

One light-year is the distance that light travels in vacuum
in one year. It's a unit of distance.

3 0

3 years ago

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A patient who smokes has hypertension. how could smoking have contributed to the patients hypertension

elena-14-01-66 [18.8K]

The nicotine in cigarette smoke is a big part of hypertension. It raises your blood pressure and heart rate, makes your arteries more narrow and hardens their walls, and also makes your blood more likely to clot. Hope this answers the question.

6 0

2 years ago

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A ball of mass 0.150 kg is dropped from rest from a height of 1.25 m. It rebounds from the floor to reach a height of 0.665 m. W

Liula [17]

Answer:

Impulse is 1.239 kg.m/s in upward direction

Explanation:

Taking upward motion as positive and downward motion as negative.

Downward motion:

Given:

Mass of ball (m) = 0.150 kg

Displacement of ball (S) = -1.25 m

Initial velocity (u) = 0 m/s

Acceleration is due to gravity (g) = -9.8 m/s²

Using equation of motion, we have:

$v_d^2=u^2+2aS\\\\v=\pm\sqrt{u^2+2aS}\\\\v_d=\pm\sqrt{0+2\times -9.8\times -1.25}\\\\v_d=\pm\sqrt{24.5}=\pm4.95\ m/s$

Since, the motion is downward, final velocity must be negative. So,

$v_d=-4.95\ m/s$

Upward motion:

Given:

Displacement of ball (S) = 0.665 m

Initial velocity ( $v_d$ ) = 4.95 m/s(Upward direction)

Acceleration is due to gravity (g) = -9.8 m/s²

Using equation of motion, we have:

$v_{up}^2=v_d^2+2aS\\\\v_{up}=\pm\sqrt{v_d^2+2aS}\\\\v_{up}=\pm\sqrt{24.5+2\times -9.8\times 0.665}\\\\v_{up}=\pm\sqrt{10.966}=\pm3.31\ m/s$

Since, the motion is upward, final velocity must be positive. So,

$v_{up}=3.31\ m/s$

Now, impulse is equal to change in momentum. So,

Impulse = Final momentum - Initial momentum

$J=m(v_{up}-v_d)\\\\J=(0.150\ kg)(3.31-(-4.95))\ m/s\\\\J=0.150\ kg\times 8.26\ m/s\\\\J=1.239\ Ns$

Therefore, the impulse given to the ball by the floor is 1.239 kg.m/s in upward direction.

5 0

3 years ago

Two identical light springs with spring constant k3 are now individually hung vertically from the ceiling and attached at each e

anyanavicka [17]

Answer:

Keq = 2k₃

Explanation:

We can solve this exercise using Newton's second one

F = m a

Where F is the eleatic force of the spring F = - k x

Since we have two springs, they are parallel or they are stretched the same distance by the object and the response force Fe is the same for the spring age due to having the same displacement

F + F = m a

k₃ x + k₃ x = m a

a = 2k₃ x / m

To find the effective force constant, suppose we change this spring to what creates the cuddly displacement

Keq = 2k₃

6 0

3 years ago

A nautical mile is 6076 feet, and 1 knot is a unit of speed equal to 1 nautical mile/hour. How fast is a boat going 8 knots goin

mezya [45]

Answer:

The speed of the boat is equal to 13.50 ft/s.

Explanation:

given,

1 nautical mile = 6076 ft

1 knot = 1 nautical mile /hour

1 knot = 6076 ft/hr

speed of boat = 8 knots

8 knots = 8 nautical mile /hour

= $8 \times \dfrac{6076\ ft}{1\nautical\ mile}\times \dfrac{1\ hour}{60\times 60\ s}$

= 13.50 ft/s

The speed of the boat is equal to 13.50 ft/s.

5 0

3 years ago