Answer:
If R₂=25.78 ohm, then R₁=10.58 ohm
If R₂=10.57 then R₁=25.79 ohm
Explanation:
R₁ = Resistance of first resistor
R₂ = Resistance of second resistor
V = Voltage of battery = 12 V
I = Current = 0.33 A (series)
I = Current = 1.6 A (parallel)
In series
![\text{Equivalent resistance}=R_{eq}=R_1+R_2\\\text {From Ohm's law}\\V=IR_{eq}\\\Rightarrow R_{eq}=\frac{12}{0.33}\\\Rightarrow R_1+R_2=36.36\\ Also\ R_1=36.36-R_2](https://tex.z-dn.net/?f=%5Ctext%7BEquivalent%20resistance%7D%3DR_%7Beq%7D%3DR_1%2BR_2%5C%5C%5Ctext%20%7BFrom%20Ohm%27s%20law%7D%5C%5CV%3DIR_%7Beq%7D%5C%5C%5CRightarrow%20R_%7Beq%7D%3D%5Cfrac%7B12%7D%7B0.33%7D%5C%5C%5CRightarrow%20R_1%2BR_2%3D36.36%5C%5C%20Also%5C%20R_1%3D36.36-R_2)
In parallel
![\text{Equivalent resistance}=\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}\\\Rightarrow {R_{eq}=\frac{R_1R_2}{R_1+R_2}](https://tex.z-dn.net/?f=%5Ctext%7BEquivalent%20resistance%7D%3D%5Cfrac%7B1%7D%7BR_%7Beq%7D%7D%3D%5Cfrac%7B1%7D%7BR_1%7D%2B%5Cfrac%7B1%7D%7BR_2%7D%5C%5C%5CRightarrow%20%7BR_%7Beq%7D%3D%5Cfrac%7BR_1R_2%7D%7BR_1%2BR_2%7D)
![\text {From Ohm's law}\\V=IR_{eq}\\\Rightarrow R_{eq}=\frac{12}{1.6}\\\Rightarrow \frac{R_1R_2}{R_1+R_2}=7.5\\\Rightarrow \frac{R_1R_2}{36.36}=7.5\\\Rightarrow R_1R_2=272.72\\\Rightarrow(36.36-R_2)R_2=272.72\\\Rightarrow R_2^2-36.36R_2+272.72=0](https://tex.z-dn.net/?f=%5Ctext%20%7BFrom%20Ohm%27s%20law%7D%5C%5CV%3DIR_%7Beq%7D%5C%5C%5CRightarrow%20R_%7Beq%7D%3D%5Cfrac%7B12%7D%7B1.6%7D%5C%5C%5CRightarrow%20%5Cfrac%7BR_1R_2%7D%7BR_1%2BR_2%7D%3D7.5%5C%5C%5CRightarrow%20%5Cfrac%7BR_1R_2%7D%7B36.36%7D%3D7.5%5C%5C%5CRightarrow%20R_1R_2%3D272.72%5C%5C%5CRightarrow%2836.36-R_2%29R_2%3D272.72%5C%5C%5CRightarrow%20R_2%5E2-36.36R_2%2B272.72%3D0)
Solving the above quadratic equation
![\Rightarrow R_2=\frac{36.36\pm \sqrt{36.36^2-4\times 272.72}}{2}](https://tex.z-dn.net/?f=%5CRightarrow%20R_2%3D%5Cfrac%7B36.36%5Cpm%20%5Csqrt%7B36.36%5E2-4%5Ctimes%20272.72%7D%7D%7B2%7D)
![\Rightarrow R_2=25.78\ or\ 10.57\\ If\ R_2=25.78\ then\ R_1=36.36-25.78=10.58\ \Omega\\ If\ R_2=10.57\ then\ R_1=36.36-10.57=25.79\Omega](https://tex.z-dn.net/?f=%5CRightarrow%20R_2%3D25.78%5C%20or%5C%2010.57%5C%5C%20If%5C%20R_2%3D25.78%5C%20then%5C%20R_1%3D36.36-25.78%3D10.58%5C%20%5COmega%5C%5C%20If%5C%20R_2%3D10.57%5C%20then%5C%20R_1%3D36.36-10.57%3D25.79%5COmega)
∴ If R₂=25.78 ohm, then R₁=10.58 ohm
If R₂=10.57 then R₁=25.79 ohm
Answer:
4 quarts = 3.784 L
Explanation:
We have given in the question,
1 quart equals about 0.946 L
1 quart = 0.946 L
thus, for finding value of 4 quarts multiply 4 on both the sides of the above equation.
4 × 1 quart = 4 × 0.946 L
4 quarts = 3.784 L
Hence, in the 4 quarts of milk contains 3.784 L of milk.
Answer:
hope that it helps
Explanation:
A. can accurately recall memories of early childhood and infancy.
Answer:
70 km
Explanation:
Before answering, let's remind the difference between distance and displacement:
- Distance: the total length of the path covered, no matter in which direction
- Displacement: the distance in a straigth line between the final point and the starting point of the motion
In this problem, we are asked to find the total distance travelled. So, we can simply add the length of the two parts of the path, regardless of their direction:
d = 30 km + 40 km = 70 km