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lisabon 2012 [21]
3 years ago
13

What is the acceleration of a 1.5 kg football thrown with a force of 13.00 N to the

Physics
1 answer:
nignag [31]3 years ago
5 0

Answer:

The acceleration of football is 6.00 m/s².

Explanation:

The acceleration can be calculated using the following equation:

\Sigma F = ma

Where:

F: is the force

m: is the mass

a: is the acceleration

F_{e} - F_{w} = ma

13.00 N - 4.00 N = 1.5 kg*a

a = \frac{9.00 N}{1.5 kg} = 6.00 m/s^{2}

Therefore, the acceleration of football is 6.00 m/s².

I hope it helps you!

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RUDIKE [14]

Answer: Hello, The opposite of rebel is  supporter, adherent.

Explanation:

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Brandon has a Nissan GTR. He drives 198.5 miles in 2.3 hours. What is his average speed?
gulaghasi [49]
86.3 I just did the math and that’s the answer I got
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What are the methods that are used for heat transfer
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Explanation:

Hope this helps

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3 years ago
Energy is conventionally measured in Calories as well as in joules. One Calorie in nutrition is one kilocalorie, defined as 1 kc
Sergeeva-Olga [200]

Answer:

a) The student must run flight of stairs to lose 1.00 kg of fat 709.5 times.

b) Average power

P(w)= 1062.07 [w]

P(hp)=1.42 [hp]

c) This activity is highly unpractical, because the high amount of repetitions he has to due in order to lose, just 1 Kg of fat.

Explanation:

First, lets consider the required amount of work to move the mass of the student. (considering running stairs just as a vertical movement)

Work:

W= F*d= m*g*d

Where m is the mass of the student, g is gravity (9.8 m/s) and d is the total distance going up the stairs (0.15m *85steps= 12.75m )

W= F*d= m*g*d=85* 9.8*12.75=10620.75 [J]

Converting from Joules to Kcals:

\frac{10620.75}{4186} =2.537 Kcal

Now lets take into account the efficiency of the human body (20%)

2.537 ---> 20%

 x       ---> 100%

x=\frac{2.537*100}{20} =12.685

So the student is consuming 12.685 KCals each time he runs up the stairs.

Now,

1 g --> 9 Kcals

1000 g --> 9000KCals

Burning 1 g of fat, requieres 9 KCals, 1000g burns 9000KCals. So in order to burn a 1Kg of fat:

\frac{9000Kcals}{12.685Kcals} =709.5 times

He must run up the stairs 709.5 times, to burn 1 Kg of fat.

********************

For b) just converting units, taking into account the time lapse. (53103.75 is the 100% of the energy in joules, from converting 12.685Kcals to joules)

Power=\frac{Joules}{Seconds} =\frac{53103.75}{50} =1062.075 [W]\\

P(hp)=\frac{P(w)}{745.7} =\frac{1062.075}{745.7} =1.42[hp]

*****

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3 years ago
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Margarita [4]

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Similarly, when you rub a balloon on your head it causes opposite static charges to build up both on your hair and the balloon. Consequently, when you pull the balloon slowly away from your head, you can see these two opposite static charges attracting one another and making your hair stand up.

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