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lisabon 2012 [21]
3 years ago
13

What is the acceleration of a 1.5 kg football thrown with a force of 13.00 N to the

Physics
1 answer:
nignag [31]3 years ago
5 0

Answer:

The acceleration of football is 6.00 m/s².

Explanation:

The acceleration can be calculated using the following equation:

\Sigma F = ma

Where:

F: is the force

m: is the mass

a: is the acceleration

F_{e} - F_{w} = ma

13.00 N - 4.00 N = 1.5 kg*a

a = \frac{9.00 N}{1.5 kg} = 6.00 m/s^{2}

Therefore, the acceleration of football is 6.00 m/s².

I hope it helps you!

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the average power of the Sun is 3.79x1026 Watts, answer the following questions: 13. What is the average intensity of light at E
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Explanation:

Given that,

Average power of sun P=3.79\times10^{26}\ Watt

We need to calculate the intensity of light at Earth's position

Using formula of intensity

I=\dfrac{P_{avg}}{4\pi r^2}

Where, I = intensity

P = power

Put the value into the formula

I=\dfrac{3.79\times10^{26}}{4\pi\times(1.496\times10^{11})^2}

I=1347.616\ W/m^2

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(A). We need to calculate the pressure on a solar sail due to the light of the sun if it's fully reflective

Using formula for fully reflective

P = \dfrac{2I}{c}

Put the value into the formula

P=\dfrac{2\times1347.616}{3\times10^{8}}

P=8.984\times10^{-6}\ N/m

(B).  We need to calculate the pressure on a solar sail due to the light of the sun if it's fully reflective

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3 years ago
A solid conducting sphere of radius 2 cm has a charge of 8microCoulomb. A conducting spherical shell of inner radius 4 cm andout
nika2105 [10]

Answer:

C) 7.35*10⁶ N/C radially outward

Explanation:

  • If we apply the Gauss'law, to a spherical gaussian surface with radius r=7 cm, due to the symmetry, the electric field must be normal to the surface, and equal at all points along it.
  • So, we can write the following equation:

       E*A = \frac{Q_{enc} }{\epsilon_{0}} (1)

  • As the electric field must be zero inside the conducting spherical shell, this means that the charge enclosed by a spherical gaussian surface of a radius between 4 and 5 cm, must be zero too.
  • So, the +8 μC charge of  the solid conducting sphere of radius 2cm, must be compensated by an equal and opposite charge on the inner surface of the conducting shell of total charge -4 μC.
  • So, on the outer surface of the shell there must be a charge that be the difference between them:

        Q_{enc} = - 4e-6 C - (-8e-6 C) = + 4 e-6 C

  • Replacing in (1) A = 4*π*ε₀, and Qenc = +4 μC, we can find the value of E, as follows:

      E = \frac{1}{4*\pi*\epsilon_{0} } *\frac{Q_{enc} }{r^{2} } = \frac{9e9 N*m2/C2*4e-6C}{(0.07m)^{2} } = 7.35e6 N/C

  • As the charge that produces this electric field is positive, and the electric field has the same direction as the one taken by a positive test charge under the influence of this field, the direction of the field is radially outward, away from the positive charge.
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How does a bimetallic strip work in a sinple alarm system​
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The bimetallic strip in a fire alarm is made of two metals with different expansion rates bonded together to form one piece of metal. Typically, the low-expansion side is made of a nickel-iron alloy called Invar, while the high-expansion side is an alloy of copper or nickel. The strip is electrically energized with a low-voltage current. When the strip is heated by fire, the high-expansion side bends the strip toward an electrical contact. When the strip touches that contact, it completes a circuit that triggers the alarm to sound. The width of the gap between the contacts determines the temperature that will set off the alarm.
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galben [10]

Answer:a

Explanation:

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Answer: Often lightning occurs between clouds or inside a cloud. But the lightning we usually care about most is the lightning that goes from clouds to ground.

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