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lisabon 2012 [21]
3 years ago
13

What is the acceleration of a 1.5 kg football thrown with a force of 13.00 N to the

Physics
1 answer:
nignag [31]3 years ago
5 0

Answer:

The acceleration of football is 6.00 m/s².

Explanation:

The acceleration can be calculated using the following equation:

\Sigma F = ma

Where:

F: is the force

m: is the mass

a: is the acceleration

F_{e} - F_{w} = ma

13.00 N - 4.00 N = 1.5 kg*a

a = \frac{9.00 N}{1.5 kg} = 6.00 m/s^{2}

Therefore, the acceleration of football is 6.00 m/s².

I hope it helps you!

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Một oto đang chuyển động thẳng đều với vận tốc 36km/h thì hãm phanh sau 20s thì ô tô dừng lại quãng đường oto đi được là
saw5 [17]
36km/h=10m/s
v=s/t=>s=200m
3 0
3 years ago
Joe rides his bicycle in a straight line for 2 hour with an average velocity of 13 km/h south, how far has he ridden?
dmitriy555 [2]

Answer:

ans is 3.125 km

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8 0
3 years ago
An open organ pipe is 1.6m long. If the speed of sound is 343m/s, what are the pipes: a) fundamental , b) 1st overtone , & c
Yakvenalex [24]

Answer:

a) 107.1875 Hz

b) 214.375 Hz

c) 321.5625 Hz

Explanation:

L = length of the open organ pipe = 1.6 m

v = speed of sound = 343 m/s

f = fundamental frequency

fundamental frequency is given as

f = \frac{v}{2L}

inserting the values

f = \frac{343}{2(1.6)}

f = \frac{343}{2(1.6)}

f = 107.1875 Hz

b)

first overtone is given as

f' = 2f

f' = 2 (107.1875)

f' = 214.375 Hz

c)

first overtone is given as

f'' = 3f

f'' = 3 (107.1875)

f'' = 321.5625 Hz

3 0
3 years ago
A 0.48 kg circus monkey is about to be shot from a cannon as part of his thrilling circus act. Draw a free body diagram labeling
Alenkinab [10]
What is it that you need help on?
6 0
2 years ago
Three masses are located in the x- y plane as follows: a mass of 6 kg is at (0 m, 0 m), a mass of 4 kg is at (3 m, 0 m), and a m
enot [183]

Answer:

The center of mass of three mass in the x-y plane is located at (1,0.5).                  

Explanation:

It is given that, a mass of 6 kg is at (0,0), a mass of 4 kg is at (3,0), and a mass of 2 kg is at (0,3). We need to find the center of mass of the system. Center of mass in x direction  is :

C_x=\dfrac{6\times 0+4\times 3+2\times 0}{6+4+2}\\\\C_x=1

The center of mass in y direction is :

C_y=\dfrac{6\times 0+4\times 0+2\times 3}{6+4+2}\\\\C_y=0.5

So, the center of mass of three mass in the x-y plane is located at (1,0.5).

3 0
3 years ago
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