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seraphim [82]
3 years ago
7

Suppose that the collector is held at a small negative voltage with respect to the grid. Will the accelerated electrons reach th

e collecting plate?
A) Yes, but only those electrons with energy less than the potential difference established between the grid and the collector will reach the collector.
B) Yes, but only those electrons with energy greater than the potential difference established between the grid and the collector will reach the collector.
C) Yes; all the accelerated electrons will reach the collector.
D) No, none of the electrons will reach the collector
Physics
1 answer:
Leona [35]3 years ago
3 0

Answer:

B) Yes, but only those electrons with energy greater than the potential difference established between the grid and the collector will reach the collector.

Explanation:

In the case when the collector would held at a negative voltage i.e. small with regard to grid So yes the accelerated electrons would be reach to the collecting plate as the kinetic energy would be more than the potential energy that because of negative potential

so according to the given situation, the option b is correct

And, the rest of the options are wrong

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The electric field between two parallel plates is uniform, with magnitude 628 N/C. A proton is held stationary at the positive p
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Answer:

Answer is explained in the explanation section below.

Explanation:

Solution:

Data Given:

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Solution:

First of all:

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and, we know that, F = ma

So,

m_{p}a = q_{p}E

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So,

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Here, u = 0.

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S = 1/2 x (\frac{q_{p}.E }{m_{p} }  )t^{2}      Equation 2

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Similarly, the distance covered by electron will be:

(D-S) = 1/2 x (\frac{q_{e}.E }{m_{e} }  )t^{2}    Equation 3

We know that the charge of electron is equal to the charge of proton so,

q_{p} = q_{e} = q

By dividing the equation 2 by equation 3, we get:

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Answer:

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