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Aleksandr [31]
3 years ago
5

What would be 1/2 times 800?

Physics
1 answer:
IgorLugansk [536]3 years ago
7 0

Answer:

The answer is 400

Explanation:

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What is the acceleration of a 600,000 kg freight train, if each of itsthree engines can provide 100,000 n of force?
sergey [27]

The acceleration of a 600,000 kg freight train, if each of its three engines can provide 100,000N of force is 0.167m/s².

<h3>How to calculate acceleration?</h3>

The acceleration of a freight train can be calculated using the following formula:

Force = mass × acceleration

According to this question, a 600,000kg freight train can produce 100,000N of force. The acceleration is as follows:

100,000 = 600,000 × a

100,000 = 600,000a

a = 0.167m/s²

Therefore, the acceleration of a 600,000 kg freight train, if each of its three engines can provide 100,000N of force is 0.167m/s².

Learn more about acceleration at: brainly.com/question/12550364

#SPJ1

6 0
1 year ago
A person walking covers 5 m ikn 10 s how fast is the person moving
aniked [119]

Not what I'd call 'fast' at all.

Speed = (distance covered) / (time to cover the distance) .

Speed = (5 meters) / (10 seconds)

<em>Speed = 0.5 meter per second</em> .

That's like about 1.1 mile per hour .

Normal walking speed is considered to be around 1.4 m/s ... about 3.1 mph, or 14 meters in 10 seconds.

I've got a grandson who hasn't even turned 1 yet.  He crawls and  doesn't walk, but if you only cover 5m in 10s, he'd leave you in the dust pretty quick.

5 0
3 years ago
a boy is standing 4 meter from a plane mirror how far and in what distance must te move so that he will be 4 meter from his imag
Alona [7]

Answer:

2 meters towards the mirror.

Explanation:

In a plane mirror the image distance is equal to the object distance. Therefore, by moving 2 meters towards the mirror, the boy reduces the distance between him and the mirror to two meters which is the object distance. The image distance is also 2 meters. add the two distances you will get four meters.

6 0
3 years ago
Find the final temperature of 375 grams of tea (c = 4.184 J/g°C) if its initial temperature is 95°C just before it is placed in
Minchanka [31]

Answer:

the final temperature of the tea is 7.39⁰C.

Explanation:

Given;

mass of the tea, m = 375 g

specific heat capacity of the tea, C = 4.184 JJ/g°C

initial temperature of the tea, t₁ = 95°C

the final temperature of the tea, t₂ = ?

Energy lost by the refrigerator, Q = 137,460 J

The energy lost by the refrigerator is given by the following formula;

-Q = mc(t₂ - t₁)

-137,460 =375 x 4.184(t₂ - 95°C)

-137,460 = 1569(t₂ - 95°C)

t_2-95 = \frac{-137,460}{1569} \\\\t_2-95 = -87.61\\\\t_2 = -87.61 + 95\\\\t_2 = 7.39 \ ^0 C

Therefore, the final temperature of the tea is 7.39⁰C.

4 0
3 years ago
A bus travels east for 3 km the north for 4 km what is its final displacement
lesya [120]
Im about to the math for this right now.
8 0
2 years ago
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