Answer:
The electric potential of the uniformly charge disk is 1392.1 V
Explanation:
Electric potential, for a uniformly charged disk at a distance A, is given as;
![V = \frac{\sigma}{2 \epsilon} [\sqrt{A^2 +R^2} -A]](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B%5Csigma%7D%7B2%20%5Cepsilon%7D%20%5B%5Csqrt%7BA%5E2%20%2BR%5E2%7D%20-A%5D)
Where;
σ is the charge density = 1.40 μC/m³
ε is the permittivity of free space = 8.85 x 10⁻¹²
A is the distance above the disk = 40 cm = 0.4 m
R is the radius of the disk = 0.12 m
Substitute in these values into the equation above, we will have
![V = \frac{1.4 X 10^{-6}}{2X8,85X10^{-12}}[\sqrt{0.4^2 +0.12^2}-0.4] \\\\V = (79096.05)(0.0176) = 1392.1 V](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B1.4%20X%2010%5E%7B-6%7D%7D%7B2X8%2C85X10%5E%7B-12%7D%7D%5B%5Csqrt%7B0.4%5E2%20%2B0.12%5E2%7D-0.4%5D%20%5C%5C%5C%5CV%20%3D%20%2879096.05%29%280.0176%29%20%3D%201392.1%20V)
Therefore, the electric potential of the uniformly charge disk is 1392.1 V
D = 110 m, t = 5 s
v o = 110 cs : 5 m = 22 m/s
-------------------------------------
v = v o - a t
v = 0 m/s, v o = 22 m/s, t = 4 s
0 = 22 - 4 a
4 a = 22
a = 22 : 4
a = 5.5 m/s²
g = 9.80 m/s²
9.80 : 5.5 = 0.56
Answer:
The magnitude of its acceleration is 5.5 m/s or 0.56 g.
Answer:
C)0.59 N
Explanation:
By the Achemides principle we know that the buoyancy force on an object which is immersed in a incompressible fluid at rest is equal to the weight of the fluid displaced. So all we have to do is to find the mass of 60ml.
Density = mass / volume
Mass = density × volume
= 1 g/cm³× 60 cm³
{ as 1ml=1cm³}
= 60 g
So force equals to,
Force = weight = mass × gravitational acceleration
= 0.06×9.8 = 0.59 N
Answer:
Potential Energy = x = m g h
Kinetic energy = 1/2 m v^2
Assuming the mass fall from rest
1/2 m v^2 = m g h
v^2 = 2 g h
So the speed attained is independent of the mass
Also, x / v does not have the units of mass
So the solution is none of the above.
You will get 20460000 as your answer which is broken down into, 2.046 x 10^7 as your number has to be between 1-10.
