If one branch of a 120-v power lines is protected by a 20-A fuse, will the fuse carry an 8-Ώ load
1 answer:
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To solve this problem we will apply the concepts related to the intensity included as the power transferred per unit area, where the area is the perpendicular plane in the direction of energy propagation.
Since the propagation occurs in an area of spherical figure we will have to
Replacing with the given power of the Bulb of 100W and the radius of 2.5m we have that
The relation between intensity I and
Here,
= Permeability constant
c = Speed of light
Rearranging for the Maximum Energy and substituting we have then,
Finally the maximum magnetic field is given as the change in the Energy per light speed, that is,
Therefore the maximum value of the magnetic field is
Answer:
E = 0 r <R₁
Explanation:
If we use Gauss's law
Ф = ∫ E. dA = / ε₀
in this case the charge is distributed throughout the spherical shell and as we are asked for the field for a radius smaller than the radius of the spherical shell, therefore, THERE ARE NO CHARGES INSIDE this surface.
Consequently by Gauss's law the electric field is ZERO
E = 0 r <R₁