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4 years ago

What is the major organic product obtained from the following sequence of reactions? PhCH2CHO PhCH2CH2CHO PhCH2CH2COOH PhCH2COOH

Chemistry

1 answer:

yarga [219]4 years ago

8 0

Answer:

PhCH2CH2COOH

Explanation:

This is a reaction of PhCH2CH2Br with KCN in the presence of H3O^+. The reaction first leads to the formation of PhCH2CH2CN.

We must recall that part of the properties of nitriles is that they can be converted to carboxylic acids in the presence of H3O^+. This is a common synthetic route for carboxylic acids.

Therefore, when the PhCH2CH2CN is now further reacted with H3O^+, the carboxylic acid PhCH2CH2COOH is formed as the major organic product of the reaction, hence the answer given above.

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Aleks [24]

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2 years ago

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tatiyna

Answer:

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3 years ago

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When a 3.80 g sample of C8H18(l) is burned in a bomb calorimeter, the temperature of the calorimeter rises by 27.3 oC. The heat

Fudgin [204]

Answer: The enthalpy of the reaction is -5112.5 kJ/mol

Explanation:

To calculate the heat absorbed by the calorimeter, we use the equation:

$q=c\Delta T$

where,

q = heat absorbed

c = heat capacity of calorimeter = 6.18 kJ/°C

$\Delta T$ = change in temperature = 27.3°C

Putting values in above equation, we get:

$q=6.18kJ/^oC\times 27.3^oC=168.714kJ$

Heat absorbed by the calorimeter will be equal to the heat released by the reaction.

Sign convention of heat:

When heat is absorbed, the sign of heat is taken to be positive and when heat is released, the sign of heat is taken to be negative.

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of octane = 3.80 g

Molar mass of octane = 114 g/mol

Putting values in above equation, we get:

$\text{Moles of octane}=\frac{3.80g}{114g/mol}=0.033mol$

To calculate the enthalpy change of the reaction, we use the equation:

$\Delta E=\frac{q}{n}$

where,

q = amount of heat released = -168.714 kJ

n = number of moles = 0.033 moles

$\Delta E$ = enthalpy change of the reaction

Putting values in above equation, we get:

$\Delta E=\frac{-168.714kJ}{0.033mol}=-5112.5kJ/mol$

Hence, the enthalpy of the reaction is -5112.5 kJ/mol

4 0

3 years ago

Balance the following equation: C7H602 + 02 -- CO2 + H20

azamat

Answer:

Explanation:

2C7H6O2 + 15O2 → 14CO2 + 6H2O.

5 0

3 years ago

Which of the following could be the name of the substance in box ‘c` choose only one box:

pentagon [3]

I would say carbon monoxide
Firstly because the image shows two different atoms bonded so it cannot be nitrogen or krypton
Secondly sulphur dioxide has 3 atoms bonded (two oxygens and a sulphur atom) so it can’t be that
Finally it can’t be hydrogen chloride because chloride is significantly larger than hydrogen
Thus it must be carbon monoxide as carbon and oxygen are bonded (CO) and are both relatively similar in size

7 0

3 years ago